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dusya [7]
3 years ago
6

The rate law for the decomposition of phosphine () is It takes 135. s for 1.00 M to decrease to 0.250 M. How much time is requir

ed for 3.00 M to decrease to a concentration of 0.450 M
Chemistry
1 answer:
vova2212 [387]3 years ago
8 0

Answer:

189.71 secs

Explanation:

We know that decomposition is a first order reaction;

So;

ln[A] = ln[A]o - kt

But;

[A]o = 1.00 M

[A] = 0.250 M

t =135 s

Hence;

ln[A] -  ln[A]o = kt

k = ln[A] -  ln[A]o/t

k = ln(1) - ln(0.250)/135

k =0 - (-1.386)/135

k = 1.386/135

k= 0.01

So time taken now will be;

ln[A] -  ln[A]o = kt

t = ln[A] -  ln[A]o/k

t = ln (3) - ln(0.450)/0.01

t = 1.0986 - (-0.7985)/0.01

t = 1.0986 + 0.7985/0.01

t = 189.71 secs

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8 0
3 years ago
The heat of vaporization Δ1, of toluene (C6H5CH3) is 38.1 kJ/mol. Calculate the change in entropy AS when 207. g of toluene boil
AveGali [126]

Answer: The change in entropy change when 207 g of toluene boils at 110.6^{o}C is 223 J/K.

Explanation:

It is given that mass of toulene is 207 g and its molar mass is 92.14 g/mol. So, its moles will be calculated as follows.

     No. of moles = \frac{mass}{\text{molar mass}}

                           = \frac{207 g}{92.14 g/mol}

                           = 2.25 moles

As we are given that heat of vaporization for 1 mol is 38.1 kJ/mol. So, heat of vaporization for 2.25 moles will be calculated as follows.

            2.25 moles \times 38.1 KJ/mol

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Now, we know that the relation between enthalpy change and entropy change is as follows.

           \Delta S = \frac{\Delta H}{\Delta T}

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Thus, we can conclude that the change in entropy change when 207 g of toluene boils at 110.6^{o}C is 223 J/K.

7 0
3 years ago
2 Points
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Answer:

A. Attractive forces called hydrogen bonds

Explanation:

5 0
3 years ago
Read 2 more answers
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anastassius [24]
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If a body was lying on their back when they died, and was moved to their front after 12 hours, where would one see the skin disc
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Explanation:

If the body remains at a position for long hours, the parts of the body which is nearest to  the ground can develop a skin discoloration as a result of pooling of blood in the tissues and this is called livor mortis, which tends to be permanent from 8Hours upwards.

8 0
3 years ago
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