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dusya [7]
3 years ago
7

Round decimals using place value chart​

Mathematics
1 answer:
sergey [27]3 years ago
7 0

here is the place values

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A person invests 10000 dollars in a bank. The bank pays 5.5% interest compounded
Blizzard [7]

Answer:

Step-by-step explanation:

4000 years

8 0
3 years ago
A³b² a²b simplify the following expression
liberstina [14]

Answer:

a^{5}b^{3}

Step-by-step explanation:

The law of indices can be used to simplify mathematical expressions involving  arithmetical operation on variables with powers.

a^{m} x a^{n} = a^{(m+n)}

Thus, the given expression can be simplified as follows:

a³b² a²b  = a³ x a² x b² x b^{1}

               = a^{3+2} x b^{2+1}

               = a^{5}b^{3}

Thus,

a³b² a²b  = a^{5}b^{3}

7 0
2 years ago
Help 15 points!!!!!!!!!!!!!!!!!!!!!
Svetllana [295]

Answer:

see explanation

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan A = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{7}{8} , then

∠ A = tan^{-1} (\frac{7}{8} ) ≈ 41° ( to the nearest degree )

The sum of the angles in the triangle = 180° , then

∠ B + 41° + 90° = 180°

∠ B + 131° = 180° ( subtract 131° from both sides )

∠ B = 49°

Using Pythagoras' identity in the right triangle

AB² = BC² + AC² = 7² + 8² = 49 + 64 = 113 ( take square root of both sides )

AB = \sqrt{113} ≈ 10.6 ( to the nearest tenth )

3 0
3 years ago
tims math homework is on five consecutive pages in the math textbook, and the sum of those page numbers is 630. what is the page
Brrunno [24]

Answer:129

Step-by-step explanation:

630/5 is 126. Add 126, two numbers below it, and two above it. So, 124+125+126+127+128=630. The next page is 129

3 0
3 years ago
does the following system of equations have a solution if so find it. 2x+y+z= 4 x-y+3z= -2 -x+y+z= -2
saul85 [17]
I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).

Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system

 - y + 3z = -2
   y  + z  =  -2
-----------------
         4z = -4, so z = -1.

Next, multiply the 3rd equation by 2:  You'll get -2x + 2y + 2z = -2.

Add this result to the first equation.  The 2x terms will cancel, leaving you with the system

2y + 2z = -2
  y  +  z  = 4

This would be a good time to subst. -1 for z.  We then get:

-2y - 2 = -2.  Then y must be 0.  y = 0.

Now subst. -1 for z and 0 for y in any of the original equations.

For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.

Then a tentative solution is     (-3, -1, 0).

It's very important that you ensure that this satisfies all 3 of the originale quations.
5 0
3 years ago
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