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3 years ago

Construction company uses 7/8 gallon of paint for each wall and are painting 8 wall how many gallons is needed

Mathematics

1 answer:

daser333 [38]3 years ago

3 0

Answer:

7 gallons

Step-by-step explanation:

1) so we know that each wall requires 7/8 gallons of paint

and for 8 walls, we can either add 7/8, 8 times or we can multiply 7/8 with 8

7/8*8/1=56/8=7

7 gallons of paint are needed

hope this helps!

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The date of death for a widow was 2019. If the estate was valued at $2,186,000 and the estate was taxed at 40 percent, what was

Airida [17]

Answer:

Value of tax liability will be zero

Step-by-step explanation:

Given:

Total estate value = $2,186,000

Estate tax = 40 %

Find:

Heir's tax liability = ?

Computation:

Total taxable estate = Total estate value - Estate Exemption

Note: According to Exhibit 19-6 for Estate Exemption, Estate Exemption is 11.4 million.

We know that Estate Exemption is higher than total estate value, therefore will be no tax liability on the successor, so the value of tax liability will be zero.

7 0

2 years ago

Solve the system of equations by graphing. {y=x-6 {y=3x-8 Show work please

Zepler [3.9K]

You should subtract left sides and right sides in order to make y disappeared
and you will have the following:

y - y = (x - 6) - (3x - 8) => 0 = x - 6 - 3x - 8 => 0 = -2x - 14 =>

2x = -14 => x = -14/2 = -7

Now you can use -7 in the system and you will get y
y = -7 - 6 = -13

So your answers will be:
x=-7 and y=-13

7 0

2 years ago

A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o

balu736 [363]

Answer:

$P(X \ge 1) = 0.509$

$P(X \ge 1) = 0.6807$

Step-by-step explanation:

From the question we are told that

The number of students in the class is N = 20 (This is the population )

The number of student that will cheat is k = 3

The number of students that he is focused on is n = 4

Generally the probability distribution that defines this question is the Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally probability mass function is mathematically represented as

$P(X = x) = \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}$

Here C stands for combination , hence we will be making use of the combination functionality in our calculators

Generally the that he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

Here

$P(X \le 0) = \frac{ ^{3} C_0 * ^{20 - 3} C_{4- 0}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ ^{3} C_0 * ^{17} C_{4}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ 1 * 2380}{ 4845}$

$P(X \le 0) = 0.491$

Hence

$P(X \ge 1) = 1 - 0.491$

$P(X \ge 1) = 0.509$

Generally the that he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

$P(X \ge 1) =1- [ \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]$