This is the graph of the equation
Find the image of A(6, -4) after it is reflected over the line y = - 2, then reflected over the line x = 1. (-4, 6) (-4, 0) (-4,
-4) (6, 2)
1 answer:
Answer:(-4,0)
Step-by-step explanation:
Given
Point A (6,-4)
Reflection of Point A about line y=-2 is
A' (6,0)
If any Point is reflected about any line y=constant then its x coordinate remains same
Now reflection of Point A' about x=1 is
A'' (-4,0)
If any point is reflected about line x=constant then its y coordinate remains same
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Answer:
Step-by-step explanation:
step 1
In the right triangle ABC
Applying the Pythagoras Theorem fin the hypotenuse AC
substitute
step 2
we know that
If two figures are similar, then the ratio of its corresponding sides is equal
so
substitute and solve for CE
step 3
Find the length of segment AE
AE=AC+CE
substitute the values