Answer:
Graph A is correct
Step-by-step explanation:
p(x)= x/10
x= 1, 2, 3, 4
Plug in x values in p(x)
when x=1 , then P(1) = 1/10
When x=2 , then P(2) = 2/10
When x=3 , then P(3) = 3/10
When x=4 , then P(4) = 4/10
In the graph y axis has 2/10 , 4/10 , 6/10...
1/10 lies between 0 and 2/10
3/10 lies between 2/10 and 4/10
Graph A is correct
Y = x² + 7x - 4
y = -x - 4
x² + 7x - 4 = -x - 4
+ x + x
x² + 8x - 4 = -4
+ 4 + 4
x² + 8x = 0
x(x) + x(8) = 0
x(x + 8) = 0
x = 0 or x + 8 = 0
- 8 - 8
x = -8
y = -x - 4
y = -0 - 4
y = 0 - 4
y = -4
(x, y) = (0, -4)
or
y = -x - 4
y = -(-8) - 4
y = 8 - 4
y = 4
(x, y) = (-8, 4)
The solutions are (0, -4) and (8, -4).
Idk but it can't be 10 or 9.7 bc a triangle's hypotenuse is always longer than its legs
Answer:
x=18
Step-by-step explanation:
6-x=-12
Subtracting 6 from both sides
-x=-12-6
-x= -18
Dividing both sides by -1
x=18
Yes it can. It doesn't <em>have to be</em>, but it can be without too much trouble.
In fact, ALL rhombuses are quadrilaterals.
