The nth term is 6n^2-11n+16
Answer: i don't see the problem
Step-by-step explanation:
Answer:
y= -2/3x-4
Step-by-step explanation:
Let us check series : -10 /-2 = 5 -50/-10 = 5
so it is a geometric series with a= -2 and r= 5
sum formula for n terms of geometric series = a ( r^n -1 ) /( r-1)
here we find S5 that is n= 5 = -2 ( 5^ 5 - 1) /( 5-1)
= -2 ( 3125 -1) / 4 = -1562
second series is : 1.5/1 = 1.5 2.25/1.5 = 1.5
this is also geometric series but n = 12 a= 1 and r= 1.5
we use same formula
S12 = 1 ( (1.5) ^12 -1) /( 1.5-1) =
128.74 / 0.5 = 257.49
Last is 2/1= 2 4/2 = 2 8/4 = 2 so r = 2 a = 1 and n = 12
we use same formula 1 ( 2^12 - 1) / (2-1)
= 4095
Answers : -1562 , 257.49 , 4095
1.)
Between year 0 and year 1, we went from $50 to $55.
$55/$50 = 1.1
The price increased by 10% from year 0 to year 1.
Between year 2 and year 1, we went from $55 to $60.50.
$60.50/$55 = 1.1
The price also increased by 10% from year 1 to year 2. If we investigate this for each year, we will see that the price increases consistently by 10% every year.
The sequence can be written as an = 50·(1.1)ⁿ
2.) To determine the price in year 6, we can use the sequence formula we established already.
a6 = 50·(1.1)⁶ = $88.58
The price of the tickets in year 6 will be $88.58.