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tensa zangetsu [6.8K]
2 years ago
15

Brass is an alloy formed using copper and zinc in the ratio 3:2 based on weight. If 120g of copper are needed for a certain piec

e of brass, how much zinc is needed?
PLEASE HELP!!
Mathematics
2 answers:
OLga [1]2 years ago
6 0

Answer:

80g of Zinc will be needed with 120g of Copper

Step-by-step explanation:

icang [17]2 years ago
3 0
Hey There :)

We can solve by 2 ways ( The 2nd way might be easier )

→ To make 1 brass alloy, the ratio of copper to zinc is 3 : 2
Brass = copper + zinc
          =       3     :    2
                   3x   :    2x
   
Copper needed is 120g
    ↓
3x = 120g
Divide by 3 to isolate x
\frac{3x}{3} = \frac{120}{3} 
x = 40

Ratio of Zinc is 2

substitute 40 in place of x
2x = 2 ( 40 ) = 80g

Or 

→ 3     :    2
     120 :    p

Cross multiply
3p = 120 x 2
3p = 240
\frac{3p}{3} = \frac{240}{3}
p = 80g

80g of Zinc will be needed with 120g of Copper

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3 years ago
Apply The Remainder Theorem, Fundamental Theorem, Rational Root Theorem, Descartes Rule, and Factor Theorem to find the remainde
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9514 1404 393

Answer:

  possible rational roots: ±{1/3, 2/3, 1, 4/3, 2, 3, 4, 6, 12}

  actual roots: -1, (2 ±4i√2)/3

  no turning points; no local extrema

  end behavior is same-sign as x-value end-behavior

Step-by-step explanation:

The Fundamental Theorem tells us this 3rd-degree polynomial will have 3 roots.

The Rational Root Theorem tells us any rational roots will be of the form ...

  ±{factor of 12}/{factor of 3} = ±{1, 2, 3, 4, 6, 12}/{1, 3}

  = ±{1/3, 2/3, 1, 4/3, 2, 3, 4, 6, 12} . . . possible rational roots

Descartes' Rule of Signs tells us the two sign changes mean there will be 0 or 2 positive real roots. Changing signs on the odd-degree terms makes the sign-change count go to 1, so we know there is one negative real root.

The y-intercept is 12. The sum of all coefficients is 22, so f(1) > f(0) and there are no positive real roots in the interval [0, 1]. Synthetic division by x-1 shows the remainder is 22 (which we knew) and all the quotient coefficients are all positive. This means x=0 is an upper bound on the real roots.

The sum of odd-degree coefficients is 3+8=11, equal to the sum of even-degree coefficients, -1+12=11. This means that -1 is a real root. Synthetic division by x+1 shows the remainder is zero (which we knew) and the quotient coefficients alternate signs. This means x=-1 is a lower bound on real roots. The quotient of 3x^2 -4x +12 is a quadratic factor of f(x):

  f(x) = (x +1)(3x^2 -4x +12)

The complex roots of the quadratic can be found using the quadratic formula:

  x = (-(-4) ±√((-4)^2 -4(3)(12)))/(2(3)) = (4 ± √-128)/6

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__

The graph in the third attachment (red) shows there are no turning points, hence no relative extrema. The end behavior, as for any odd-degree polynomial with a positive leading coefficient, is down to the left and up to the right.

4 0
3 years ago
The sum of the first 130 positive even integers
Triss [41]

Answer:

Step-by-step explanation:

Positive integers are of the form 2n

The first term is 2 and the 130th term is 2(130)=260

The sum of this arithmetic sequence is the average of first and last terms times the number of terms

(2+260)(130/2)

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7 0
3 years ago
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Andreas93 [3]
The answer would be 14, because 1.75 x 8= 14
6 0
3 years ago
SOMEONE PLEASE HELP ME ASAP PLEASE!!!​
Strike441 [17]

Answer:

105.12 ft^2

Step-by-step explanation:

Area of a rectangle: bh

In this case 8*10.... so area of the rectangle is 80

Area of a circle: pir^2

Half it for a semicircle.

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so 1/2(3.14)(4^2)=(0.5)(3.14)(16)=25.12

Now add up 80+25.12

Total is 105.12

Hope I helped :)

5 0
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