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zepelin [54]
3 years ago
13

In a two-digit number, the units digit is twice the tens digit. If the number is doubled, it will be 9 more than the number reve

rsed. Find the number. :) Thanks!
Mathematics
2 answers:
snow_lady [41]3 years ago
6 0
We know that the ones digit is 2x the tens digit. The number has to be two digits, so this leaves the options of 12, 24, 36, and 48.

Next, we double each number.
12 x 2 is 24
24 x 2 is 48
36 x 2 is 72
48 x 2 is 96

And subtract 9 from each of those. 15, 39, 63, and 87.

63 backwards is 36. The number you are looking for is 36. :)
taurus [48]3 years ago
5 0
10(2x)+x 
21x is the original number

12x is the reversed number
24x is the reversed then doubled number

Set up an equation:
24x=21x+9
3x=9
x=3

The original number is 63 and the reversed number is 36, which then is 72 when doubled.
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You pick a card at random from an ordinary deck of 52 cards. If the card is an ace, you get 9 points; if not, you lose 1 point.
Andreyy89

Answer:

a = 9\\b = 48\\c = -1

Step-by-step explanation:

We know that:

In a deck of 52 cards there are 4 aces.

Therefore the probability of obtaining an ace is:

P (x) = 4/52

The probability of not getting an ace is:

P ('x) = 1-4 / 52

P ('x) = 48/52

In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.

For a discrete random variable V, the expected value is defined as:

E(V) = VP(V)

Where V is the value that the random variable can take and P (V) is the probability that it takes that value.

We have the following equation for the expected value:

E(V) = \frac{4}{52}(a) + \frac{b}{52}(c)

In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52

Therefore, expected value for V, the number of points obtained in the game is:

E(V) = \frac{4}{52}(9) + \frac{48}{52}(-1)

So:

a = 9\\b = 48\\c = -1

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