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zepelin [54]
3 years ago
13

In a two-digit number, the units digit is twice the tens digit. If the number is doubled, it will be 9 more than the number reve

rsed. Find the number. :) Thanks!
Mathematics
2 answers:
snow_lady [41]3 years ago
6 0
We know that the ones digit is 2x the tens digit. The number has to be two digits, so this leaves the options of 12, 24, 36, and 48.

Next, we double each number.
12 x 2 is 24
24 x 2 is 48
36 x 2 is 72
48 x 2 is 96

And subtract 9 from each of those. 15, 39, 63, and 87.

63 backwards is 36. The number you are looking for is 36. :)
taurus [48]3 years ago
5 0
10(2x)+x 
21x is the original number

12x is the reversed number
24x is the reversed then doubled number

Set up an equation:
24x=21x+9
3x=9
x=3

The original number is 63 and the reversed number is 36, which then is 72 when doubled.
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The output from a statistical computer program indicates that the mean and standard deviation of a data set consisting of 200 me
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Answer:

The limit that 97.5% of the data points will be above is $912.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1500, \sigma = 300

Find the limit that 97.5% of the data points will be above.

This is the value of X when Z has a pvalue of 1-0.975 = 0.025. So it is X when Z = -1.96.

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Z = \frac{X - \mu}{\sigma}

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The limit that 97.5% of the data points will be above is $912.

6 0
3 years ago
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