The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
Learn more on polynomial here: brainly.com/question/2833285
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Answer:
you have to find the smallest common denominator
Step-by-step explanation:
so once the fractions have the same denominator you can add them easily and simplify
An outlier number is the number that's completely different from the rest.
For example;
1, 15, 17, 16, 14.
"1" is the outlier.
Our list of numbers range (on average) from 7-12.
Let's look at our answer choices.
A.) There is one outlier that indicates an unusually large number of players on that team.
This is true, as we have 21, the one and only outlier in our list.
Your answer is A.)
I hope this helps!
B.
<span>$5852.86
Working;
</span><span>A = P(1 + r)^t
A=5000(1+</span>
)^5
A=<span>5852.86</span>
