Answer:
12 glasses can be hold
Step-by-step explanation:
Find the Amount of quarts equal to fluid ounces
After you find it divide the number to 8
Brainliest is needed plz
Answer:
![\large \boxed{\ \ \dfrac{63}{5} \ \ }](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5C%20%5C%20%5Cdfrac%7B63%7D%7B5%7D%20%5C%20%5C%20%7D)
Step-by-step explanation:
Hello,
"Find the sum of the following infinite geometric series"
infinite
We will have to find the limit of something when n tends to ![+\infty](https://tex.z-dn.net/?f=%2B%5Cinfty)
geometric series
This is a good clue, meaning that each term of the series follows a geometric sequence. Let's check that.
The sum is something like
![\displaystyle \sum_{k=0}^{+\infty} a_k](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csum_%7Bk%3D0%7D%5E%7B%2B%5Cinfty%7D%20a_k)
First of all, we need to find an expression for ![a_k](https://tex.z-dn.net/?f=a_k)
First term is
![a_0=7](https://tex.z-dn.net/?f=a_0%3D7)
Second term is
![a_1=\dfrac{4}{9}\cdot a_0=7*\boxed{\dfrac{4}{9}}=\dfrac{7*4}{9}=\dfrac{28}{9}](https://tex.z-dn.net/?f=a_1%3D%5Cdfrac%7B4%7D%7B9%7D%5Ccdot%20a_0%3D7%2A%5Cboxed%7B%5Cdfrac%7B4%7D%7B9%7D%7D%3D%5Cdfrac%7B7%2A4%7D%7B9%7D%3D%5Cdfrac%7B28%7D%7B9%7D)
Then
![a_2=\dfrac{4}{9}\cdot a_1=\dfrac{28}{9}*\boxed{\dfrac{4}{9}}=\dfrac{28*4}{9*9}=\dfrac{112}{81}](https://tex.z-dn.net/?f=a_2%3D%5Cdfrac%7B4%7D%7B9%7D%5Ccdot%20a_1%3D%5Cdfrac%7B28%7D%7B9%7D%2A%5Cboxed%7B%5Cdfrac%7B4%7D%7B9%7D%7D%3D%5Cdfrac%7B28%2A4%7D%7B9%2A9%7D%3D%5Cdfrac%7B112%7D%7B81%7D)
and...
![a_3=\dfrac{4}{9}\cdot a_2=\dfrac{112}{81}*\boxed{\dfrac{4}{9}}=\dfrac{112*4}{9*81}=\dfrac{448}{729}](https://tex.z-dn.net/?f=a_3%3D%5Cdfrac%7B4%7D%7B9%7D%5Ccdot%20a_2%3D%5Cdfrac%7B112%7D%7B81%7D%2A%5Cboxed%7B%5Cdfrac%7B4%7D%7B9%7D%7D%3D%5Cdfrac%7B112%2A4%7D%7B9%2A81%7D%3D%5Cdfrac%7B448%7D%7B729%7D)
Ok we are good, we can express any term for k integer
![a_k=a_0\cdot (\dfrac{4}{9})^k](https://tex.z-dn.net/?f=a_k%3Da_0%5Ccdot%20%28%5Cdfrac%7B4%7D%7B9%7D%29%5Ek)
So, for n positive integer
![\displaystyle \sum_{k=0}^{n} a_k=\displaystyle \sum_{k=0}^{n} 7\cdot (\dfrac{4}{9})^k=7\cdot \dfrac{1-(\dfrac{4}{9})^{n+1}}{1-\dfrac{4}{9}}=\dfrac{7*9*[1-(\dfrac{4}{9})^{n+1}]}{9-4}=\dfrac{63}{5}\cdot [1-(\dfrac{4}{9})^{n+1}}]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csum_%7Bk%3D0%7D%5E%7Bn%7D%20a_k%3D%5Cdisplaystyle%20%5Csum_%7Bk%3D0%7D%5E%7Bn%7D%207%5Ccdot%20%28%5Cdfrac%7B4%7D%7B9%7D%29%5Ek%3D7%5Ccdot%20%5Cdfrac%7B1-%28%5Cdfrac%7B4%7D%7B9%7D%29%5E%7Bn%2B1%7D%7D%7B1-%5Cdfrac%7B4%7D%7B9%7D%7D%3D%5Cdfrac%7B7%2A9%2A%5B1-%28%5Cdfrac%7B4%7D%7B9%7D%29%5E%7Bn%2B1%7D%5D%7D%7B9-4%7D%3D%5Cdfrac%7B63%7D%7B5%7D%5Ccdot%20%5B1-%28%5Cdfrac%7B4%7D%7B9%7D%29%5E%7Bn%2B1%7D%7D%5D)
And the limit of that expression when n tends to
is
![\large \boxed{\ \ \dfrac{63}{5} \ \ }](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5C%20%5C%20%5Cdfrac%7B63%7D%7B5%7D%20%5C%20%5C%20%7D)
as
![\dfrac{4}{9}](https://tex.z-dn.net/?f=%5Cdfrac%7B4%7D%7B9%7D%3C1)
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Find 110% of 40
we already see the 100, so it's 40 + x
so 10% of 40 is 40*.10 which is 4
so it's 40+4
44 is 110% of 40.
Another way of finding this is just multiplying 40*1.10 on a calculator or by hand.
Answer:
ok
Step-by-step explanation:
Answer:
r1= -10 r2= +10 (10)
Step-by-step explanation:
r²= 165-65
r²= 100
r=+-(root)100
r1= -10
r2= +10 (10)