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sveta [45]
3 years ago
10

What is the product? (9t − 4)(−9t − 4) −81t2 − 16 −81t2 16 −81t2 − 72t 16 −81t2 72t 16

Mathematics
1 answer:
Alexxandr [17]3 years ago
5 0
<span>We have to find the product : ( 9 t - 4 ) ( - 9 t - 4 ) = - ( 9 t - 4 ) ( 9 t + 4 ) After that we can use the difference of squares. The formula is: ( a + b ) ( a - b ) = a^2 - b^2. In this case: - ( 9 t - 4 ) ( 9 t + 4 ) = - ( 81 t^2 - 16 ) = - 81 t^2 + 16 . Answer: B ) - 81 t^2 + 16.</span>
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Think about converting 48% to an equivalent fraction in reduced form. If the denominator is 25, what is the numerator?
bulgar [2K]

Answer:

the numerator is 12

Step-by-step explanation:

since 48 is a percent, it would be put as 48/100 as a fraction. since both the numerator and denominator are divisible by 4, you can reduce the fraction into 12/25. Since the question is asking what the numerator was when the denominator was 25, the answer is 12.

8 0
3 years ago
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kherson [118]

Step-by-step explanation: Isolate the variable by dividing each side by factors that don't contain the variable.

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2 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%28x%20-%20%20%5Cfrac%7B2%7D%7B9%7D%20%29%28x%20%2B%20%20%5Cfrac%7B1%7D%7B2%7
Aleonysh [2.5K]
f(x) = (x -  \dfrac{2}{9} )(x +  \dfrac{1}{2} )

\text {When } f(x) = 0 :

(x -  \dfrac{2}{9} )(x +  \dfrac{1}{2} ) = 0

(x -  \dfrac{2}{9} ) = 0  \text { or }  (x +  \dfrac{1}{2} ) = 0

x =  \dfrac{2}{9}  \text { or } x =  -\dfrac{1}{2}

3 0
3 years ago
Solve for x.<br> 3(x+3) = -18 . A. x= -9<br> B.x= -7<br> c. x=-5<br> D. X=-3
slavikrds [6]

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3 0
3 years ago
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prisoha [69]

Answer:

X=-2or,-3

Step-by-step explanation:

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or,x^2+(2+3)x+6=0

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or,x(x+2)+3(x+2)=0

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I HOPE IT WILL HELP YOU

7 0
3 years ago
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