I think it's 5x(x^3+4x^2-21x)
We can solve by figuring the area of the rectangle then add it to the area of the semicircle.
Area of the rectangle: length · width = 6 · 10 = 60 ft²
Area of the semicircle: (πd²)/8 = (3.14 · 6²)/8 = (3.14 · 36)/8 = 14.13 ft²
Total area of the figure: 60 + 14.13 = 74.13 ft² ≈ 74 ft²
Slope is rise/ run and rise/run is y/x. c?
2/5 and 1/2 can go into 10.
So, 2/5*2 = 4/10
and, 1/2*5 = 5/10.
Got it?
