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NARA [144]
3 years ago
14

The weights (in pounds) of six dogs are listed below.

Mathematics
2 answers:
tresset_1 [31]3 years ago
6 0
First, we know it can't be median because 72 is not a value in the data. If you find the mean/average, you will find that it is 72
ANSWER: Mean/average
azamat3 years ago
6 0

Answer:

The measure of center is the average or mean.

Step-by-step explanation:

The weights (in pounds) of six dogs are listed below.  

17 56 85 38 138 98

Arranging in ascending order, we get

17  38 56 85 98 138

The measure of center is found to be 72 lb.

This is the average or mean. We can check this as:

\frac{17+38+56+85+98+138}{6} =72

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4 years ago
Solve the system by substitution.<br> [-2.5x+y = 13.5<br> 12.25x - y=-12.25
IrinaK [193]

Answer:

x = 5/39 , y = 539/39

Step-by-step explanation:

Solve the following system:

{y - 2.5 x = 13.5

12.25 x - y = -12.25

In the first equation, look to solve for y:

{y - 2.5 x = 13.5

12.25 x - y = -12.25

y - 2.5 x = y - (5 x)/2 and 13.5 = 27/2:

y - (5 x)/2 = 27/2

Add (5 x)/2 to both sides:

{y = 1/2 (5 x + 27)

12.25 x - y = -12.25

Substitute y = 1/2 (5 x + 27) into the second equation:

{y = 1/2 (5 x + 27)

1/2 (-5 x - 27) + 12.25 x = -12.25

(-5 x - 27)/2 + 12.25 x = 12.25 x + (-(5 x)/2 - 27/2) = 9.75 x - 27/2:

{y = 1/2 (5 x + 27)

9.75 x - 27/2 = -12.25

In the second equation, look to solve for x:

{y = 1/2 (5 x + 27)

9.75 x - 27/2 = -12.25

9.75 x - 27/2 = (39 x)/4 - 27/2 and -12.25 = -49/4:

(39 x)/4 - 27/2 = -49/4

Add 27/2 to both sides:

{y = 1/2 (5 x + 27)

(39 x)/4 = 5/4

Multiply both sides by 4/39:

{y = 1/2 (5 x + 27)

x = 5/39

Substitute x = 5/39 into the first equation:

{y = 539/39

x = 5/39

Collect results in alphabetical order:

Answer: {x = 5/39 , y = 539/39

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3 years ago
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Alekssandra [29.7K]

Answer:

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Step-by-step explanation:

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