3\4
because the spaces are bigger draw a model and you will see
Answer:
-259
Step-by-step explanation:
brainliest
Answer:
if you have to add it is 17
if you have to divide it is 1.5
if you have to subtract it is 16
Step-by-step explanation:
Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:
The slopes of WX and XZ
Step-by-step explanation:
The singular factor that determines if the parallelogram is a rectangle are the angles at the edges
Mathematically, we can only have a rectangle if there are four right angles with one right angle each at the edges of the rectangle
So, by having the slope of the sides forming the width and that which forms the length, we can deduce if what we have is rectangle given that the slopes will yield a perpendicular product
Hence, the slopes of WX and XZ can be calculated to show this
