Answer:
I'm going to say its 31668
The volume of the right squared pyramid with the given base edges and slant height is 32768 cubic centimeters.
<h3>What is the volume of right square pyramid?</h3>
The volume of a square pyramid is expressed as;
V = (1/3)a²h
Where a is the base length and h is the height of the pyramid
Given that;
- Base edges of the square base a = 64cm
- Slant height s = 40cm
- Height of the pyramid h = ?
- Volume = ?
First, we determine the height of the pyramid using Pythagorean theorem.
c² = a² + b²
- c = s = 40cm
- a = half of the base length = a/2 = 64cm/2 = 32cm
- b = h
(40cm) = (32cm)² + h²
1600cm² = 1024cm² + h²
h² = 1600cm² - 1024cm²
h² = 576cm²
h = √576cm²
h = 24cm
Now, we calculate the volume of the right square pyramid;
V = (1/3)a²h
V = (1/3) × (64cm)² × 24cm
V = (1/3) × 409664cm² × 24cm
V = 32768cm³
Therefore, the volume of the right squared pyramid with the given base edges and slant height is 32768 cubic centimeters.
Learn more about volume of pyramids here: brainly.com/question/27666514
#SPJ1
Answer:
p = 4.0
q = 2.0
angle <P = 64 degrees
Step-by-step explanation:
We can use the definition of cosine to find the value of side p (the adjacent side to the 26 degree angle, via the formula:
which rounded to the nearest tenth gives : p = 4.0
Now we use the sine function to help us determine side q:
which rounded to the nearest tenth gives:
q = 2.0
Finally, we determine the measure of angle P using the fact that the addition of all internal angles of a triangle must add to 180 degrees:
< P + < Q + < R = 180
< P + 26 + 90 = 180
< P = 180 - 26 - 90
< P = 64 degrees
<span>A(C)=9x^2-25/3x+5 = [3x+5)(3x-5)] / (3x -5) = 3x + 5
</span><span>The zero of the function,
3x + 5 = 0
3x = -5
x = -5/3
answer
</span><span>-5/3</span>
