Answer:
A batch of 20 semiconductor chips is inspected by choosing a sample of 3 chips. Assume 10 of the chips do not conform to customer requirements.
a) Number of different samples = 20C3 = =1140
b) 2 good and one bad chip
Number of samples = 10C2 * 10C1 = 45 * 10 =450
c) 2 good 1 bad + 1 good 2 bad + 3 bad
Number of samples = 10C2 * 10C1 + 10C1 * 10C2 + 10C3
=
For number 25 it’s x=4 and for 26 it’s x=7
4x - 12
You can get this by switch the f(x) and the x and then solving for the new f(x)
The nearest hundred thousand is 3,700,000
And the nearest million is 4,000,00
Answer:
C. c = 64 + 2w
Step-by-step explanation:
You're starting with 64 customers and you're gaining 2 for each week.
<em>good luck, i hope this helps :)</em>