I need help please it’s due today I forgot how to do this :(
1 answer:
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Answer:
Step-by-step explanation:
We are given the equation of the line y=3x and a point, say Q(60,0) outside of that line.
We want to find the point on the line y=3x which is closest to Q.
Let P(x,y) be the desired point. Since it is on the line y=3x, it must satisfy the line.
If x=a, y=3a, so the point P has the coordinates (a,3a).
Distance between point Q and P
To minimize D, we find its derivative
Therefore, the y-coordinate for P is 3*6=18.
The point P=(6,18).
Next, we calculate the distance between P(6,18) and (60,0).
Answer:
The given inequality is
Let y be a Real number such that 9 less than two third of that number is less than one added to that number.
We can find solution of the inequality also
1. keeping variable on one side and constant on another side, which gives
→y - > -9 -1
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