Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
Answer:
1. 4 and 4sqrt2
2. 6sqrt2 and 6sqrt2
3. 5 and 5sqrt2
4. 5sqrt2 and 5sqrt2
5. 6 and 6
6. 8 and 8sqrt2
7. sqrt3 and sqrt6
8. sqrt2 and sqrt4
Step-by-step explanation:
Answer:
31
Step-by-step explanation:
Divide 3 from both sides to get a=57/3 then a=19
Answer:
4.5 x 0.85 = 3.825
Step-by-step explanation:
