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PolarNik [594]
3 years ago
14

Please help, multiple choice question

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
3 0
The correct answer is:
y\leq -2x+2
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Karma baked 48 cookies yesterday. Every hour, she bakes another batch of 12 cookies. What is the rate of change for the scenario
Alja [10]
+8 x 5 - 12 i am not sure tho if it is supposed to be one i am sorry i can't really help you but ill look into it
5 0
3 years ago
On a baseball
vampirchik [111]

Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.

<h3>How far did the outfielder throw the ball?</h3>

Based on the shape of a mound, the law of cosines can be used.

The distance the ball was thrown by the outfielder can therefore be d.

Distance is:

d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))

d ²= 33,484.42ft

Then find the square root:

d = √33,484.42

= 182.9874

= 183 ft

Find out more solving for distance at brainly.com/question/10739348

#SPJ1

4 0
2 years ago
Need help please on geometry
zimovet [89]
To solve this we are going to use the formula for the area of a circle: A= \frac{1}{4} \pi d^2
where
A is the area of the circle 
d is the diameter of the circle 

We know from our problem that the area of our circle is 10 inches long, so d=10in. Lets replace that value in our formula to find A:
A=\frac{1}{4} \pi (10in)^2
A=78.54in^2

We can conclude that the correct answer is: 78.54 square inches, or in centimeters: 506.7 square cm.
4 0
3 years ago
Read 2 more answers
the diameters of Douglas firs grown at a Christmas tree farm are normally distributed with a mean of 4 inches and a standard dev
aksik [14]

Answer:

Proportion of the trees will have diameters between 2 and 6 inches = 0.8164

Step-by-step explanation:

Given -

Mean (\nu )  = 4

Standard deviation (\sigma  ) = 1.5

Let X be the diameter of tree

proportion of the trees will have diameters between 2 and 6 inches =

P(2<  X<  6)   =  P(\frac{2 - 4 }{1.5}< \frac{X - \nu }{\sigma}<  \frac{6 - 4 }{1.5})

                         = P(\frac{-2 }{1.5}< Z<  \frac{2 }{1.5})     Put  [Z = \frac{X - \nu }{\sigma}]

                         =  P(-1.33< Z<  1.33)

                          = (Z<  1.33) - (Z<  -1.33)

                          = .9082 - .0918

                           = 0.8164

6 0
3 years ago
Factor the Following:<br><br>1.) 8<br>2.) -12<br>3.) -3y²<br>4.) 6x²+36x<br>5.) 7x -14x²​
Alex787 [66]

Answer:

1.) 8 = 8

2.) -12 = -12

3.) -3y² = -3y²

4.) 6x² + 36x = 6x(x + 6)

5.) 7x - 14x² = 7x(1 - 2x)

~

3 0
3 years ago
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