+8 x 5 - 12 i am not sure tho if it is supposed to be one i am sorry i can't really help you but ill look into it
Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
#SPJ1
To solve this we are going to use the formula for the area of a circle:

where

is the area of the circle

is the diameter of the circle
We know from our problem that the area of our circle is 10 inches long, so

. Lets replace that value in our formula to find

:


We can conclude that the correct answer is: 78.54 square inches, or in centimeters: 506.7 square cm.
Answer:
Proportion of the trees will have diameters between 2 and 6 inches = 0.8164
Step-by-step explanation:
Given -
Mean
= 4
Standard deviation
= 1.5
Let X be the diameter of tree
proportion of the trees will have diameters between 2 and 6 inches =
= 
=
Put [
]
= 
= 
= .9082 - .0918
= 0.8164
Answer:
1.) 8 = 8
2.) -12 = -12
3.) -3y² = -3y²
4.) 6x² + 36x = 6x(x + 6)
5.) 7x - 14x² = 7x(1 - 2x)
~