Answer:
a^5x^5, 10a^5x^4, 40a^5x^3
Step-by-step explanation:
Use pascal's triangle for the first one
(2+x)^5 * a^5
= x^5a^5 + 5*2^1*x^4*a^5 + 10*2^2*x^3*a^5 ...
= a^5x^5 + 10a^5x^4+ 40a^5x^3 ...
Slope: -4
Y-intercept : (0, -10)
X will be the speed of species b and 4x will be the speed of species a:
x + 4x = 180
5x = 180
x = 180 / 5
x = 36 m/h
If species b has a speed of 36 m/h, the speed of species a is 4 times that:
4 x 36 = 144 m/h.
Answer:

Hope it helped,
Happy homework/ study/ exam!
Answer:
Everything but A and C
Step-by-step explanation:
A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.