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Andreas93 [3]
3 years ago
15

Whats the factors of 13

Mathematics
1 answer:
ivann1987 [24]3 years ago
6 0
13 can only be divided evenly by 1 and<span> 13. its a prime number

</span>
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Liz is making beaded necklaces. for each necklace, she uses 27 spacers, plus 5 beads per inch of necklace length. write the rule
horsena [70]
Not sure if my rule will be correct, but the equation i would use would be y=27x for the spacers and y=5x for the beads.

for 18 inch: 486 spacers and 90 beads

for 24 inch: 648 spacers and 120 beads
4 0
3 years ago
It cost Makayla $2.80 to send 28 text messages. How much would it cost to send 163 text messages?
RUDIKE [14]

Answer:

$16.30

Step-by-step explanation:

Hope this helps! Have a great day!!

8 0
2 years ago
(20 POINTS) help, please and thank you! :) &lt;3
Andrei [34K]

The given points are: (-2,4) and (6,b)

The slope is -3/2

The slope is the change in Y over the change in x.

So you get:  -3/2 = (b - 4) / (6 - -2)

Simplify to get: -3/2 = (b - 4) / 8

Now we see the denominator on the right is 8 and on the left is 2, this is a scale of 4: (8 / 2 = 4) so the numerator on the right needs to be scaled by 4 as well.

The left side is -3, so the right side needs to equal -3 x 4 = -12

Now we know b - 4 = -12, solve for b:

b -4 = -12, add 4 to both sides:

b = -8

Now check:

(-2,4) (6,-8)

Slope = (-8 - 4) / (6 - -2) = -12 /8 = -3/2

b = -8

4 0
3 years ago
Does anyone know how to solve this?
Law Incorporation [45]

Answer:

{ \boxed{ \tt{f(x) = 5 \cos3x \degree}}} \\  {  \green{f(x) = f(60) : x = 60}}\\ f(60) = 5 \cos(3 \times 60) \degree \\ f(60) = 5 \cos(180 \degree)  \\ but \:  \cos(180 \degree)  =  - 1\\  { \boxed{ \bf{answer : f(60) =  - 5}}} \\  \\ { \underline{ \blue{becker \: jnr}}}

5 0
3 years ago
PLEASE HELP ME AND MY DAUGHTER
iogann1982 [59]

Answer:

0.85

Step-by-step explanation:

The interquartile range of any given data set is simply the difference between the Q3 and the Q1, i.e. Q3 - Q1.

Let's find the Q3 and the Q1 of the given data set: 30.8, 29.9, 30.0, 31.0, 30.1, 30.5, 30.7, 31.0

First, let's order the data given in increasing order from small to the largest value:

29.9, 30.0, 30.1, 30.5, 30.7, 30.8, 31.0, 31.0

Let's find the median:

Since the number of data set given is even number (8), our median would be the average of the 4th and 5th data value = (30.5+30.7) ÷ 2 = 30.6

Let's find Q3 and Q1

Q1 is the middle value from the median point to our left = (30.0+30.1) ÷ 2 = 30.05

Q3 is the middle value from the median point to our right = (30.8+31.0)÷2 = 30.9

Interquartile Range = 30.9 - 30.05 = 0.85

5 0
4 years ago
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