Two semicircles are inscribed in a square with side 8 cm as shown. Find the area of the shaded region.
1 answer:
Area of square = 8 * 8 = 64 sq cm
Circle inscribed would touch all sides, meaning the diameter is equal to the side length. Thus the radius would be half the width, or 4 cm.
Area of circle =
=
= 3.14 * 16
= 50.24 sq cm
Then remove the circle area from the square area.
64 - 50.24 = 9.76 sq cm.
This is if that is how the image looks.
Circle inscribed would touch all sides, meaning the diameter is equal to the side length. Thus the radius would be half the width, or 4 cm.
Area of circle =
=
= 3.14 * 16
= 50.24 sq cm
Then remove the circle area from the square area.
64 - 50.24 = 9.76 sq cm.
This is if that is how the image looks.
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Answer:
As we can see the z score for Ferdinad is higher than the z score for Emilia so on this case we can conclude that Ferdinand was better compared with his group of reference.
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Emilia case
Let X the random variable that represent the scores of a test, and we know that
Where and
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Since Emilia made 83 points we can find the z score like this:
Ferdinand case
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Where and
The z score formula is given by:
Since Ferdinand made 79 points we can find the z score like this:
As we can see the z score for Ferdinad is higher than the z score for Emilia so on this case we can conclude that Ferdinand was better compared with his group of reference.
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is 
The diagrams below show step by step transformation
As we can see from the graph, the amplitude of the function is 3, period of 
, phase shift of π and midline y=2
The diagrams below show step by step transformation
As we can see from the graph