The height of cylinders A and B will be 11 feet and 16.5 feet.
<h3>What is the surface area of a right circular cylinder?</h3>
Let r be the radius and h be the height of the cylinder.
Then the surface area of the cylinder will be
SA = 2πrh square units
Cylinder A has a radius of 6 feet and a height that is 5.5 feet less than Cylinder B. Cylinder B's radius is 4 feet.

The surface area of cylinder A will be
SA = 2π × 6 × 
The surface area of cylinder B will be
SA = 2π × 4 × 
The cylinders have the same surface area. Then we have
2π × 4 ×
= 2π × 6 × 

Then the height of the cylinder B will be

The height of cylinders A and B will be 11 feet and 16.5 feet.
More about the surface area of the cylinder link is given below.
brainly.com/question/22074027
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Answer:
<u>3.7</u>
Step-by-step explanation:
<u>Given</u>
- sin²θ + cos²θ = 1
- sinθ = 0.27
<u>Solving for cos</u>θ
- cos²θ = 1 - sin²θ
- cos²θ = 1 - (0.27)²
- cos²θ = 0.0729
<u>Finding tan</u>θ
- tanθ = sinθ / cosθ
- tanθ = 0.27 / 0.0729
- tanθ = <u>3.7</u>
<u>Verifying it lies in the range</u>
- θ = tan⁻¹ (3.7)
- θ = 74.88°
- Range is : 0 < θ < π/2 [or 0 < θ < 90°]
- It lies in the range [Verified]