3 years ago

If DF=9x-39 and DE=47 and EF is 3x+10 find ef

Mathematics

1 answer:

trapecia [35]3 years ago

5 0

Answer:

EF = 58

Step-by-step explanation:

Starting with the premise that

DF = DE + EF, then

9x - 39 = 47 + 3x + 10 ( subtract 3x from both sides )

6x - 39 = 57 ( add 39 to both sides )

6x = 96 ( divide both sides by 6 )

x = 16

Hence

EF = 3x + 10 = (3 × 16) + 10 = 48 + 10 = 58

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