If DF=9x-39 and DE=47 and EF is 3x+10 find ef

Mathematics

1 answer:

trapecia [35]3 years ago

5 0

Answer:

EF = 58

Step-by-step explanation:

Starting with the premise that

DF = DE + EF, then

9x - 39 = 47 + 3x + 10 ( subtract 3x from both sides )

6x - 39 = 57 ( add 39 to both sides )

6x = 96 ( divide both sides by 6 )

x = 16

Hence

EF = 3x + 10 = (3 × 16) + 10 = 48 + 10 = 58

You might be interested in

A wedding dress is on sale for $225.00, which is 25% off of its original price. What was the original price of the dress?

Olenka [21]

So if the dress is 25% off, that means you are paying 75% of the original price.

sale price = original price x 0.75
225 = original price x 0.75

divide both sides by 0.75 to isolate original price

225/0.75 = (original price x 0.75)/0.75
300 = original price

7 0

3 years ago

Read 2 more answers

The equation represents an ellipse. which point is the center of the ellipse? (−9, 5) (−5, 9) (5, −9) (9, −5)

Igoryamba

The point which is the center of the ellipse whose equation is; (y+5)²/121+(x-9)²/49=1 s in the task content is; (-5, 9).

<h3>Which point represents the center of the ellipse whose equation is given as; (y+5)²/121+(x-9)²/49=1?</h3>

It follows from convention that the equation of an ellipse usually takes the form;

(y-h)²/a²+(x-k)²/b²=1 in which case, the center of the ellipse is given by the point; (h, k).

On this note, By comparison of the actual equation and the standard equation, it follows that;

+5 = -h and consequently, h = -5,

-9 = -k and consequently, k = 9.