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VLD [36.1K]
3 years ago
14

At the beginning of the year, Vici Ventures had accounts receivable of $220,000. At the end of the year, the company had account

s receivable of $340,000. During the year, Vici had total sales of $1,000,000, 70% of which were credit sales. What was Vici's receivables turnover ratio for the year?
Business
1 answer:
garri49 [273]3 years ago
5 0

Answer:

Vici's receivables turnover ratio for the year is 2,5

Explanation:

We can calculate the  Accounts receivable turnover by dividing net credit sales by the average accounts receivable for that period.

Accounts receivable turnover= net credit sales /average accounts receivable

In this case ,  

<u>Net credit sales</u>=  70% of total sales= 70% $1,000,000= 700,000

To get average accounts receivable, add the value of accounts receivable at the beginning to the value at the end of the period and divide the sum by two

Average accounts receivable= ($220,000+$340,000)/2

<u>Average accounts receivable= $280,000</u>

Then,

Accounts receivable turnover= 700,000/$280,000=2,5

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3 years ago
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patriot [66]

Answer:

Answer to this question is b.46500

Explanation:

According to 28/36 guidelines, a household shall not spend more than 28% of its monthly income on housing expenses.

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Answer to this question is b.46500

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3 years ago
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The difference between the monthly payment of R and S is equal to $48.53 by following the compound interest formula. Thus, Loan R's monthly loan amount is greater than Loan S.

<h3>What is a Compound interest loan?</h3>

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\rm\,For\,R\\\\P = \$\,17,550\\r\,= 5.32\%\\Time\,= n= 7\,years\\Amount\,paid= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\=[ 17,550 (1+\dfrac{5.32}{100\times12})^{7\times12} ]\\= [ 17,550 (\dfrac{12.0532}{12})^{84} ]\\\\=  [ 17,550 (1.00443^{84} ]\\\\= \$ 25,440.48\\\\Total\,monthly\,payment = \rm\,\dfrac{25,440.48}{84}\\\\= \$\, $302.86\\\\

\rm\,For\,S =\\\\P=\,\$ 15,925\\r\,= 6.07\%\\T=n= 9\,years\\\\Amount\,paid\,= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\\\\= [15,925(1+\dfrac{0.0607}{12})^{9\times12} ]\\\\\\= [15,925(1+\dfrac{0.0607}{12})^{108} ]\\\\=[15,925(1.7247.84)} ]\\\\\= \$27,467.19\\\\Total\,monthly\,payment =\dfrac{\rm\,\$\,27,469.19}{108}\\\\= \$ 254.326\\\\

The difference between the monthly payment of R and S is equal to $48.53.

Hence, Loan R's monthly payment is greater than the loan's monthly payment by $48.53

To learn more about Compound interest, refer to the link:

brainly.com/question/14331235

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