The equation of the line g that passes through points (-3, 2) and (0, 5), in slope-intercept form, is: y = x + 5.
<h3>How to Write the Equation of a Line in Slope-intercept Form?</h3>
Given the coordinates of two points that lie on a straight line on a graph, the equation that represents the line in slope-intercept form can be expressed as, y = mx + b, where:
Slope = m = change in y / change in x
y-intercept = b (the value of y when x = 0).
The coordinates of the two points on line g is given as:
(-3, 2) = (x1, y1)
(0, 5) = (x2, y2).
Find the slope (m) of the line:
Slope (m) = (5 - 2)/(0 - (-3))
Slope (m) = 3/3
Slope (m) = 1.
Y-intercept (b) = 5
Substitute m = 1 and = 5 into y = mx + b:
y = x + 5
The equation of the line in slope-intercept form is: y = x + 5.
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The temperature was changing at a rate of 2.925 degrees Celsius in 2005
<h3>How to determine the rate in 2005</h3>
From the graph (see attachment), we have the following ordered pair
(x,y) = (5,14.625)
The above means that, the temperature in 2005 is 14.625 degrees Celsius
So, the rate in 2005 is:


Hence, the temperature was changing at a rate of 2.925 degrees Celsius in 2005
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Answer:
above is the answer to the question
Answe
Given,
f(x) = 49 − x² from x = 1 to x = 7
n = 4

For x= 1
f(x₀) = 49 - 1^2 = 48
x = 2.5
f(x₁) = 42.75
x = 4
f(x₂) = 49 - 4^2 = 33
x = 5.5
f(x₃) = 49 - 5.5^2 = 18.75
x = 7
f(x₄) = 49 - 7^2 = 0
We have to evaluate the function on therigh hand point
![A = \Delta x [f(x_1)+f(x_2)+f(x_3)+f(x_4)]](https://tex.z-dn.net/?f=A%20%3D%20%5CDelta%20x%20%5Bf%28x_1%29%2Bf%28x_2%29%2Bf%28x_3%29%2Bf%28x_4%29%5D)
![A = 1.5 [42.75+33+18.75+0]](https://tex.z-dn.net/?f=A%20%3D%201.5%20%5B42.75%2B33%2B18.75%2B0%5D)

For Area for left hand sum
![A = \Delta x [f(x_0)+f(x_1)+f(x_2)+f(x_3)]](https://tex.z-dn.net/?f=A%20%3D%20%5CDelta%20x%20%5Bf%28x_0%29%2Bf%28x_1%29%2Bf%28x_2%29%2Bf%28x_3%29%5D)
![A = 1.5 [48+42.75+33+18.75]](https://tex.z-dn.net/?f=A%20%3D%201.5%20%5B48%2B42.75%2B33%2B18.75%5D)
