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xeze [42]
3 years ago
14

There is a stack of 8 cards, each given a different number from 1 to 8. Suppose we select a card randomly from the stack, replac

e it, and then randomly select another card. What is the probability that the first card is an even number and the second card is greater than
6? Write your answer as a fraction in simplest form.
Mathematics
2 answers:
dimulka [17.4K]3 years ago
7 0
The probability of drawing an even number is 4/8 = 1/2 since there are 4 even cards (2,4,6,8) out of 8 total.

After the first draw, the card is put back. There are still 8 cards in the deck. There are 2 cards that are larger than 6. Those numbers are 7 and 8. So the probability of picking a card larger than 6 is 2/8 = 1/4

Multiply the two individual probabilities to get
(1/2)*(1/4) = (1*1)/(2*4) = 1/8

The final answer is 1/8
KIM [24]3 years ago
5 0
Here, Total Outcome = 8  [ For both operations ]

Number which are even between 1 & 8 = 2, 4, 6, 8
So, the probability would be: 4/8 = 1/2

Numbers which are greater than 6 = 7, 8
So, the probability would be: 2/8 = 1/4

Now, In order to have a combined probability you need to multiply the numbers, = 1/2 * 1/4 = 1/8

In short, Your Answer would be 1/8

Hope this helps!
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3 years ago
Work out(3^5-5^3+2) divided 4^2
professor190 [17]

Given:

(3^5-5^3+2) divided by 4^2.

To find:

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We have, (3^5-5^3+2) divided by 4^2. Mathematically it can be written as:

\dfrac{3^5-5^3+2}{4^2}=\dfrac{243-125+2}{16}

\dfrac{3^5-5^3+2}{4^2}=\dfrac{120}{16}

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\dfrac{3^5-5^3+2}{4^2}=7.5

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