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3 years ago

Factor the expression. 21x^2 + 43x + 20

Mathematics

2 answers:

liq [111]3 years ago

6 0

Hello,

$21x^2 + 43x + 20\\
=21x^2+28x+15x+20\\
=7x(3x+4)+5(3x+4)\\
=(3x+4)(7x+5)\\

Answer B$

krok68 [10]3 years ago

3 0

Each choice has 7x and 3x which multiply to 21x^2.
The original trinomial has positive 20 and positive 43, so all factors of 21 and of 20 must be positive.
Only choice B has all positive terms, so choice B must be the answer.

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3 years ago

I need answers!!!!!!!!

aleksandrvk [35]

Answer:

a) 4.4583 b) Fiona

Step-by-step explanation:

First find the average of the numbers by adding them all together then dividing them by the amount of numbers given:

$(85 + 88 + 90 + 91 + 93 + 96 + 97 + 97 + 98 + 98 + 99 + 105)\div12= 1137\div12= 94.75$

Then find the difference between each number and the answer you got

$(85 - 94.75) + (88 - 94.75) + (90 - 94.75) + (91 - 94.75) + (93 - 94.75) + (96 - 94.75) + (97 - 94.75) + (97 - 94.75) + (98 - 94.75) + (98 - 94.75) + (99 - 94.75) + (105 - 94.75)\div12$

Which is

$(9.75) + (6.75) + (4.75) + (3.75) + (1.75) + (1.25) + (2.25) + (2.25) + (3.25) + (3.25) + (4.25) + (10.25)\div12$

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Step-by-step explanation:

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