The debate team is showing a debate.The first showing begins at 3:15 pm.The second showing is scheduled at 4:50 pm with a 1/2 ho
2 answers:
You might be interested in
Answer:
2
Step-by-step explanation:
So I'm going to use vieta's formula.
Let u and v the zeros of the given quadratic in ax^2+bx+c form.
By vieta's formula:
1) u+v=-b/a
2) uv=c/a
We are also given not by the formula but by this problem:
3) u+v=uv
If we plug 1) and 2) into 3) we get:
-b/a=c/a
Multiply both sides by a:
-b=c
Here we have:
a=3
b=-(3k-2)
c=-(k-6)
So we are solving
-b=c for k:
3k-2=-(k-6)
Distribute:
3k-2=-k+6
Add k on both sides:
4k-2=6
Add 2 on both side:
4k=8
Divide both sides by 4:
k=2
Let's check:
:
I'm going to solve for x using the quadratic formula:
Let's see if uv=u+v holds.
Keep in mind you are multiplying conjugates:
Let's see what u+v is now:
We have confirmed uv=u+v for k=2.
Answer:
degree of polynomial = 5
leading term =
leading coefficient = 2
constant term = -6
Step-by-step explanation:
(i) The degree of the polynomial = 5. That is, the highest power of x
(ii) Leading term = . This is the term with the highest power of x.
(iii) Leading Coefficient = 2. That is, the coefficient of the leading term ()
(iv) Constant term = -6. This is the term that is independent of x or the term in which x doesn't appear.