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Dvinal [7]
3 years ago
14

The debate team is showing a debate.The first showing begins at 3:15 pm.The second showing is scheduled at 4:50 pm with a 1/2 ho

ur break between the showings.How long is the video in hours and minutes?
Can someone please help me I will appreciate it.
Mathematics
2 answers:
rjkz [21]3 years ago
6 0
1 hour and 5 minutes.
Anna [14]3 years ago
4 0
The answer is one hour and five minutes because subtract 30 minutes from 4:50 you get 4:20 the time in between is your answer (one hour five minutes
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3 0
2 years ago
joe weighs 20lbs.less yhantwice jeffs weight.if jeff would gain 10lbs.,then together they wouldweigh 250lbs. how much does each
masya89 [10]
So,

Let x represent Joe's weight and y represent Jeff's weight.

"Joe weighs 20 lbs. less than twice Jeff's weight."
x = 2y - 20

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
(y + 10) + x = 250

We now have our two open sentences.
x = 2y - 20
(y + 10) + x = 250

Get rid of parentheses.
x = 2y - 20
x + y + 10 = 250

We will use Elimination by Substitution.
2y - 20 + y + 10 = 250

Collect Like Terms.
3y - 10 = 250

Add 10 to both sides.
3y = 260

Divide both sides by 3.
Jeff's\ weight = 86 \frac{2}{3} \ lbs.

Substitute again.
x = 2(86 \frac{2}{3} )-20

Multiply.
x = 173 \frac{1}{3} -20

Subtract.
Joe's\ weight = 153 \frac{1}{3}\ lbs.

Check.

"Joe weighs 20 lbs. less than twice Jeff's weight."
Jeff's weight times two is 173 and one-third.
20 lbs. less than that is 153 and one-third lbs. Check.

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
86 and two-thirds + 10 = 96 and two-thirds.
96 and two-thirds + 153 and one-third equals 250 lbs. Check.

Joe's\ weight\ is\ 153 \frac{1}{3} \ lbs.
Jeff's\ weight\ is\ 86 \frac{2}{3} \ lbs.
3 0
3 years ago
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Talja [164]

Answer:

5 1/4

Step-by-step explanation:

8 0
3 years ago
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Margaret [11]

Answer:

BC = 11\sqrt{2}

Step-by-step explanation:

using the sine ratio in the right triangle and the exact value

sin45° = \frac{1}{\sqrt{2} } , then

sin 45° = \frac{opposite}{hypotenuse} = \frac{AC}{BC} = \frac{11}{BC} = \frac{1}{\sqrt{2} } ( cross- multiply )

BC = 11\sqrt{2}

7 0
2 years ago
Write an equation for the quotient of a number and -12
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