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2 years ago

Anyone have a link to a good 8th grade study guide for math?

Mathematics

1 answer:

Delvig [45]2 years ago

5 0

Answer:

https://newpathworksheets.com/math/grade-8

Step-by-step explanation:

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A survey of 500 students in a school found that about 100 households consist of only vegetarians, 240 consist of vegetarians and

RideAnS [48]

100+160/500 consist of only vegetarians, or only non-vegetarians, which equal 260/500=13/25 probability. ☺☺☺☺

4 0

3 years ago

Find a polynomial $f(x)$ of degree $5$ such that both of these properties hold: $\bullet$ $f(x)$ is divisible by $x^3$. $\bullet

frosja888 [35]

There seems to be one character missing. But I gather that f(x) needs to satisfy

• $x^3$ divides $f(x)$

• $(x-1)^3$ divides $f(x)^2$

I'll also assume f(x) is monic, meaning the coefficient of the leading term is 1, or

$f(x) = x^5 + \cdots$

Since $x^3$ divides $f(x)$ , and

$f(x) = x^3 p(x)$

where $p(x)$ is degree-2, and we can write it as

$f(x)=x^3 (x^2+ax+b)$

Now, we have

$f(x)^2 = \left(x^3p(x)\right)^2 = x^6 p(x)^2$

so if $(x - 1)^3$ divides $f(x)^2$ , then $p(x)$ is degree-2, so $p(x)^2$ is degree-4, and we can write

$p(x)^2 = (x-1)^3 q(x)$

where $q(x)$ is degree-1.

Expanding the left side gives

$p(x)^2 = x^4 + 2ax^3 + (a^2+2b)x^2 + 2abx + b^2$

and dividing by $(x-1)^3$ leaves no remainder. If we actually compute the quotient, we wind up with

$\dfrac{p(x)^2}{(x-1)^3} = \underbrace{x + 2a + 3}_{q(x)} + \dfrac{(a^2+6a+2b+6)x^2 + (2ab-6a-8)x +2a+b^2+3}{(x-1)^3}$

If the remainder is supposed to be zero, then

$\begin{cases}a^2+6a+2b+6 = 0 \\ 2ab-6a-8 = 0 \\ 2a+b^2+3 = 0\end{cases}$

Adding these equations together and grouping terms, we get

$(a^2+2ab+b^2) + (2a+2b) + (6-8+3) = 0 \\\\ (a+b)^2 + 2(a+b) + 1 = 0 \\\\ (a+b+1)^2 = 0 \implies a+b = -1$

Then $b=-1-a$ , and you can solve for a and b by substituting this into any of the three equations above. For instance,

$2a+(-1-a)^2 + 3 = 0 \\\\ a^2 + 4a + 4 = 0 \\\\ (a+2)^2 = 0 \implies a=-2 \implies b=1$

So, we end up with

$p(x) = x^2 - 2x + 1 \\\\ \implies f(x) = x^3 (x^2 - 2x + 1) = \boxed{x^5-2x^4+x^3}$

6 0

2 years ago

Which statement is true about point Y?

Viefleur [7K]

Answer:C

Step-by-step explanation:

3 0

3 years ago

Simply the expression: Pls need help fast!!!!!!

sukhopar [10]

Answer:

4^6

Step-by-step explanation:

6 0

2 years ago

Layla wrote a report on insects. She listed the lengths of a tiger beetles, carpenter ants, and aphids. The lengths were 1/2 inc

ahrayia [7]

First we would change the fractions into decimals and compare them. That way it would be easy to solve when needed.

1/2=0.50
5/8=0.625
1/8=0.125

Now we can see that 1/8 (0.125) is the smallest, followed by 1/2 (0.50), and 5/8 the largest. Now we can match the sizes with the insects.

Since the tiger beetle is the largest we will place that with the length of 5/8 since that is the largest.

The carpenter ant is second largest so it would be matched with 1/2

The aphid is the smallest so that would be with 1/8 as the smallest

*Hope that helped :D*

3 0

2 years ago