3 years ago

5(1-cos x)÷x Determine the limit of the transcendental function (if it exists).

Mathematics

1 answer:

luda_lava [24]3 years ago

8 0

hello here is a solution :

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3 years ago

When h has the value 4 calculate 16-3h

Westkost [7]

Substitute the 4 for h so you have:

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3 years ago

Thee vertex of a parabola is (-5,2), and its focus is (-1,2). What is the standard form of the parabola?

Alla [95]

Check the picture below. So the parabola looks more or less like so.

$\bf \textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\supset}\qquad \stackrel{"p"~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] ~\dotfill$

$\bf \begin{cases} h=-5\\ k=2\\ p=4 \end{cases}\implies 4(4)[x-(-5)]=[y-2]^2\implies 16(x+5)=(y-2)^2 \\\\\\ x+5=\cfrac{1}{16}(y-2)^2\implies x = \cfrac{1}{16}(y-2)^2-5$