For this case we have the following variables, let:
x: The greater integer
y: The minor integer
We have to:
Thus, we have a system of two equations with two unknowns. To solve, we follow the steps below:
Step 1:
We add both equations:
Thus, the smallest integer is 
Step 2:
We substitute "y" in any of the equations and clear x:
Thus, the largest integer is 
So:
Anwer:
Integer minor,
Integer greater,
The correct answer is :False
Answer:
number 2
Step-by-step explanation:
from the original equation you can multiple the m to the x's first.
y-y1=mx-mx1
if you moved mx1 to left the sign will change from - to +
so you y- y1+mx1= mx
then to get x
(y- you + mx1 )/ m = x
hope it helps
Answer:
x = 5/2 + sqrt(41)/2 or x = 5/2 - sqrt(41)/2 thus 2 is the Answer
Step-by-step explanation:
Solve for x:
x^2 - 5 x - 4 = 0
Add 4 to both sides:
x^2 - 5 x = 4
Add 25/4 to both sides:
x^2 - 5 x + 25/4 = 41/4
Write the left hand side as a square:
(x - 5/2)^2 = 41/4
Take the square root of both sides:
x - 5/2 = sqrt(41)/2 or x - 5/2 = -sqrt(41)/2
Add 5/2 to both sides:
x = 5/2 + sqrt(41)/2 or x - 5/2 = -sqrt(41)/2
Add 5/2 to both sides:
Answer: x = 5/2 + sqrt(41)/2 or x = 5/2 - sqrt(41)/2
Answer:
8.23529412
Step-by-step explanation:
Do long division to get the answer as simple as that!
