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3 years ago

MARK AS BRAINLEST FOR THE CORRECT ANSWER PLUS 13 POINTS

Mathematics

1 answer:

marishachu [46]3 years ago

8 0

Answer:

correct simulations of Tom’s scenario.

Step-by-step explanation:

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PLEASE HELP ME!A MILLION THANKS TO THE PEOPLE THAT ANSWERED ME!!.NO LINKS.WILL GIVE BRAIN IF YOU ANSWER CORRECTLY!THANK YOU SOO

azamat

Answer:

What eventually led to conflicts between settlers and American Indians in Virginia?

farmers destroying the soil with tobacco crops

farmers moving onto land close to the coast

indentured servants encroaching on settlers’ land

colonial traders charging too much for tobacco

Step-by-step explanation:

vWhat eventually led to conflicts between settlers and American Indians in Virginia?

farmers destroying the soil with tobacco crops

farmers moving onto land close to the coast

indentured servants encroaching on settlers’ land

colonial traders charging too much for tobacco

5 0

2 years ago

Read 2 more answers

Which fraction is larger 3/4 or 7/9 and find the common denominator

FrozenT [24]

Answer:

the answer is 7/9

Step-by-step explanation:

7 0

3 years ago

The graphs of f(x) and g(x) are shown below:

Alekssandra [29.7K]

Your Answer: G(x) = (x − 5)²

I just finished my semester exam, and this was one of the questions. I guessed on this question because I had no clue of what the answer was, and lucky me, I got the question right :D

Hope this helps y'all with your test :)

3 0

3 years ago

Read 2 more answers

Inverse laplace of [(1/s^2)-(48/s^5)]

Katen [24]

**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform $F(s)$ and $G(s)$ , then $\mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}$

Given that $\dfrac{1}{s^2} = \dfrac{1!}{s^2}$ and $-\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}$

From Table of Laplace Transform, you have $\mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}}$ and hence $\mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}$ .

Hope this helps...

7 0

3 years ago

Find the term that must be added to the equation x2 6x=1 to make it into a perfect square.

andrezito [222]

The value added to the equation $$x^2-6x=1$ exists $$x^2-6x+9=10$ .