9 c 10 b 11 b 12a 13 c 14 d 15 d 16c 17 a or c
18 b 19 d 20 is b
The probability of getting a cookie with no more than 3 chips is 0.714.
<h3>What is probability?</h3>
It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
We have:
Well-mixed cookie dough will produce cookies with a mean of 6 chocolate chips apiece.
Using poison ratio:

λ is the mean number of chocolate chips in a piece

P(X ≥ 5) = 1 - P(X < 5)
P(X ≥ 5) = 1 - P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)
![\rm P(X \geq 5) = 1-[\dfrac{6^0 e^{-6}}{0!}+\dfrac{6^1 e^{-6}}{1!}+\dfrac{6^2 e^{-6}}{2!}+\dfrac{6^3 e^{-6}}{3!}+\dfrac{6^4 e^{-6}}{4!}]](https://tex.z-dn.net/?f=%5Crm%20P%28X%20%5Cgeq%20%205%29%20%20%3D%20%201-%5B%5Cdfrac%7B6%5E0%20e%5E%7B-6%7D%7D%7B0%21%7D%2B%5Cdfrac%7B6%5E1%20e%5E%7B-6%7D%7D%7B1%21%7D%2B%5Cdfrac%7B6%5E2%20e%5E%7B-6%7D%7D%7B2%21%7D%2B%5Cdfrac%7B6%5E3%20e%5E%7B-6%7D%7D%7B3%21%7D%2B%5Cdfrac%7B6%5E4%20e%5E%7B-6%7D%7D%7B4%21%7D%5D)
After solving;
P(X ≥ 5) = 0.714
Thus, the probability of getting a cookie with no more than 3 chips is 0.714.
Learn more about the probability here:
brainly.com/question/11234923
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2m would be your answer
Each ticket costs $2, which means that if you are buying more tickets, it would look like: 2 + 2.... instead of the others
hope this helps
Answer:
a-bi
Step-by-step explanation:
If a quadratic equation lx^2+mx+n=0 has one imaginary root as a+bi then the other root is the conjugate of a+bi = a-bi
Because we have l, m and n are real numbers and they are the coefficients.
Sum of roots = a+bi + second root = -m/l
When -m/l is real because the ratio of two real numbers, left side also has to be real.
Since bi is one imaginary term already there other root should have -bi in it so that the sum becomes real.
i.e. other root will be of the form c-bi for some real c.
Now product of roots = (a+bi)(c-bi) = n/l
Since right side is real, left side also must be real.
i.e.imaginary part =0
bi(a-c) =0
Or a =c
i.e. other root c-bi = a-bi
Hence proved.