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Anastaziya [24]
3 years ago
8

Bismuth-210 has a half-life of about 5 days. After 15 days, how many milligrams of a 600 mg sample will remain?

Mathematics
2 answers:
raketka [301]3 years ago
5 0
Every 5 days the number is cut in half. So from 600 mg to day 5, the sample will be 300 mg. Then from day 5 to day 10, the sample will reduce to 150 mg. And finally, from day 10 to day 15, the sample will have reduced to:

75 mg

I hope this Helps!
Andrew [12]3 years ago
4 0

Answer:

75 milligrams.

Step-by-step explanation:

We have been given that Bismuth-210 has a half-life of about 5 days.

To solve our given problem we will use half-life formula.  

y=a\cdot(\frac{1}{2})^{\frac{t}{b}}, where,

a = Initial value,

t = Time,

b = half-life.

Upon substituting our given values in above formula we will get,

y=600\cdot(\frac{1}{2})^{\frac{15}{5}}  

y=600\cdot(0.5)^{3}  

y=600\cdot 0.125  

y=75  

Therefore, 75 milligrams of Bismuth-210 will remain after 15 days.

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Answer:

<em> All college freshman </em>is called <em>Population and Right handed students are excluded is called sample from Population</em>

Step-by-step explanation:

<u>Explanation</u>:-

<em>Population:</em>-  The total of the observations which we are concerned

given data <em>all college freshman </em>is called <em>Population</em>

<u><em>Sample</em></u><em> :-</em>

<em>A sample is a subset of a Population</em>

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3 years ago
Less than 75% of workers got their job through internet resume sites. A researcher thinks it has increased.
Vera_Pavlovna [14]

Answer:

H0 : p = 0.75  against    H1: p > 0.75  One tailed test.

Step-by-step explanation:

We state our null and alternative hypotheses as

H0 : p = 0.75  against    H1: p > 0.75  One tailed test.

In this case H0 is not defined as p≤ 0.75 because the acceptance and rejection regions cannot be set up. Therefore we take the exact value of H0 : p= 0.75.

The claim is that the probability of the workers getting their job through the internet is greater than 75% or 0.75.

As H0 is supposed to be less than we choose H1 to be greater than equality.

5 0
3 years ago
How would you write the equation with a slope of 2/3 and a y-intercept of (0,-3)?
rosijanka [135]

Answer:

y = (2/3)x - 3

Step-by-step explanation:

Slope-intercept form: y = mx + b

Note that:

y = (x , y)

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b = y-intercept.

The point is given to you. Note that:

(x , y) = (0 , -3) ∴

x = 0

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Plug in the corresponding numbers to the corresponding variable:

y = mx + b

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Plug in -3 for b in the equation:

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~

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3 years ago
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tiny-mole [99]

Answer:

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