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Rainbow [258]
2 years ago
14

You go to a Christmas fair with a big Ferris wheel. The wheel has ten seats, and two people are placed on each seat. Every minut

e a seat passes by the exit platform. At 11 a. M. The Ferris wheel opens for 30 minutes - how many people have ridden the wheel during this time?.
Mathematics
2 answers:
Fed [463]2 years ago
5 0
600 because 30 x 10 x 2
monitta2 years ago
3 0

60 people have ridden the wheel in 30 minutes

The time is given as:

Time =30 \minutes

The number of seats on the wheel is given as:

Seats = 10\\

The number of people on a seat is given as:

People =2

Every minute a seat exits the platform.

This means that, 2 people exit the platform every minute

So, the number (n) of people that exit the platform after 30 minutes would be:

n =People \times Time

This gives

n = 2\times 30

Multiply

n = 60

Hence, 60 people have ridden the wheel

Read more about proportions at:

brainly.com/question/25567167

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Hey!


2*2 = 4 (You doubled the 2)

8*2 = 16

16 + 16 = 32
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5*45+6856x=8x+65x+76x
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Answer:

0.033547          I think

Step-by-step explanation:

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an 80 ounce bottle of juice contains 32 ounces of water . A 64 ouce bottle of orange juice has 48 ounces of water . Which juice
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Ten weight lifters are competing in a team weight-lifting contest. Of the lifters, 3 are from the United States, 4 are from Russ
ruslelena [56]

Answer:

(a) 65536 - the basic principle of counting

(b) 2520 - use the multinomials.  

Step-by-step explanation:

Divide 8 people among 4 schools

The teachers are different among themselves, and so are the schools.  

(a)

Every teacher can choose a school. By the basic principle of counting: 4.4.4.4.4.4.4.4 = 4^8 = 65536

different divisions of the teachers

Note: this does not ensure that every school gets a teacher  

(b) - <u>Every school gets precisely 2 teachers:</u>

to divide 8 different objects into four groups of fixed sizes 2, 2, 2 and 2, use the multinomial coefficient  

( 8   2, 2, 2, 2) = (8!)/(2!2!2!2!) ==> 2520

different divisions of the teachers

5 0
3 years ago
Question 12 (1 point) Given P(A) 0.34, P(A and B) 0.27, P(A or B) 0.44, what is P(B)? Answer in decimal form. Round to 2 decimal
Tema [17]

Answer:  The required probability of event B is P(B) = 0.37.

Step-by-step explanation:  For two events A and B, we are given the following probabilities :

P(A) = 0.34,    P(A ∩ B) = 0.27   and   P(A ∪ B) = 0.44.

We are to find the probability of event B, P(B) = ?

From the laws of probability, we have

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\\Rightarrow 0.44=0.34+P(B)-0.27\\\\\Rightarrow 0.44=0.07+P(B)\\\\\Rightarrow P(B)=0.44-0.07\\\\\Rightarrow P(B)=0.37.

Thus, the required probability of event B is P(B) = 0.37.

6 0
3 years ago
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