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Alex777 [14]
3 years ago
13

Here is a diagram and its corresponding equation. Find the solution to the equation.

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
8 0

Answer: The answer would be x=5/3

Step-by-step explanation:

First you would subtract 11 from both sides, cancelling out the 11 on the left while making 21-11=10. Your equation at this point would be 6x=10. Now you would divide by 6 on both sides making the answer x=5/3.

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A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
The cross country coach later determine that the length of the football field is 120 yards. All students must run five laps. Usi
Sedaia [141]

Answer:

25.2

Step-by-step explanation:

3 0
3 years ago
you plan to cover the entire surface area of a cylindrical dart board with cork. find the surface area of the dart board if the
Assoli18 [71]
So the amount needed=area of circle times height
area formula=pi times radius^2
height=3/4

so
pi=aprox 3.14
radius=7
3.14 times 7^2
3.14 times 49
153.86
times 3/4
115.395 in^3

answer is 115.4 cubic inches


5 0
3 years ago
I seriously need help with this. I pay attention in class it's just so confusing!! I'm giving extra points. Now 15. Please tell
brilliants [131]

Answer:

D

Step-by-step explanation:

Its D because A is all 90 degrees

Not C because all 90

8 0
3 years ago
If tan x =1/2<br> find sin x<br> 2
irina1246 [14]

Answer:

t

=

26

∘

57

+

k

360

∘

Step-by-step explanation:

tan

t

=

1

2

Calculator and unit circle give 2 solutions for (0, 360) -->

t

=

26

∘

57

, and

t

=

180

+

26.57

=

206

∘

57

General answer:

t

=

26

∘

57

+

k

360

∘

6 0
3 years ago
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