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Jet001 [13]
3 years ago
7

Which statement is true?

Mathematics
1 answer:
pantera1 [17]3 years ago
4 0
The first one is all squares are rectangles and the second one is not all parallelograms are rectangles.
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HELP ASAP !I Really need help with this , can someone help me please ? I don’t quite get it & need to turn this in
marissa [1.9K]
First on is linear, second is exponential, third is exponential and the last is linear
All problems that are linear increase by a constant rate, ones that increase exponentially increase by a percentage or decimal
4 0
3 years ago
To solve a system of inequalities ayana isolated y in the first equation and then substituted for y in the second equation. what
vitfil [10]

Answer:

(- 3, - 6 ) , (1, 2 )

Step-by-step explanation:

2y = 4x ( divide both sides by 2 )

y = 2x → (1)

x² + y = 3 → (2)

Substitute y = 2x into (2)

x² + 2x = 3 ( subtract 3 from both sides )

x² + 2x - 3 = 0 ← in standard form

(x + 3)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x - 1 = 0 ⇒ x = 1

Substitute theses values into (2) for corresponding values of y

x = - 3 : y = 2(- 3) = - 6 ⇒ (- 3, - 6 )

x = 1 : y = 2(1) = 2 ⇒ (1, 2 )

8 0
3 years ago
2. Given the equation of a circle in standard form, identify the center, radius, and graph the circle.
Varvara68 [4.7K]

Answer:

Center: ( -1 , 2 )

Radius: 6

Step-by-step explanation:

The equation for a circle is given as follow:

(x-h)^{2} +(y-k)^{2} =r^{2}

Where,

the Center is: ( h , k ) (note that the signs of the number are different)

and the radius is: r

So if we compare the original circle equation to the equation in the question we can see that:

(x+1)^{2} +(y-2)^{2} =36

the Center is: (-1,2)

and the radius is: \sqrt{36} = 6

2. To draw the graph find points that lay on the circle, it's better to take the values of x and y from the Center:

first sub y=2 in the equation to find the values for x:

(x+1)^{2} +(y-2)^{2} =36

(x+1)^{2} +(2-2)^{2} =36

(x+1)^{2} +(0)^{2} =36

(x+1)^{2}  =36

x+1 =±\sqrt{36}

x=6-1    AND    x=-6-1

x=5          AND    x=-7

  • The points are A(5,2)  and  B(-7,2)

second sub x= -1 in the equation to find the values for y:

(x+1)^{2} +(y-2)^{2} =36

(-1+1)^{2} +(y-2)^{2} =36

(0)^{2} +(y-2)^{2} =36

(y-2)^{2} =36

y-2=±\sqrt{36}

y=6+2    AND    y=-6+2

y=8          AND    y=-4

  • The points are D(-1,8)  and  E(-1,-4)      

After finding the points write them in the graph and match them together to get the like the circle in the picture below:

8 0
3 years ago
Which expressions are equivalent to 2 (three-fourths x + 7) minus 3 (one-half x minus 5)? Check all that apply.
Mariulka [41]

Answer:

2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))

2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)

Step-by-step explanation:

The original expression given in the text is

2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)  (1)

And we want to check to what other expressions is equivalent. First of all, we solve it by writing explicitely each term:

\frac{3}{2}x+14-\frac{3}{2}x+15 (2)

Let's verify each of the other expressions separately. For the first one:

2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))

We see that this is equivalent to expression (1), since the first half is identical, while in the second one, the combination "+-" can be simply written as "-", so we get

2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)

Which is equivalent to (1).

For the 2nd one:

2(\frac{3}{4}x)+2(7)+3(\frac{1}{2}x)+3(-5)

This is not equivalent. In fact, here we have applied the distributive property to each term: however, the 3rd and 4th term are not correct, because the (3) must be negative (-3), as in the original expression.

If we write it explicitely in fact, we get

\frac{3}{2}x+14+\frac{3}{2}x-15

Which is different from (2).

For the 3rd one:

2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)

This one is equivalent. In fact, here we have applied the distributive property correctly. By solvign each term we get:

\frac{3}{2}x+14-\frac{3}{2}x+15

8 0
4 years ago
Read 2 more answers
A Hindu might try to live a virtuous life to _____________.
DIA [1.3K]
The answer is B. Hindus believe in the concept of reincarnation, so obtaining good karma by living a virtuous life will help a person to be reborn of a higher caste (a higher position in the social order)  in their next life.
7 0
4 years ago
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