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stealth61 [152]
3 years ago
13

PLEASE HELP ASAP!!!!!!

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
5 0
I'm not sure what the question is but it looks like it's B
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A triangular pane of glass has a height of 30 inches and an area of 270 square inches. what is the length of the base pane
Tems11 [23]
The equation for the area of a triangle is A= b*h /2. So, plug in your known variables, and you get 270in^2= b*30 /2. First you multiply by 2 to cancel out the division for 2, which gets you 540= b* 30. To get "b" by itself, divide both sides by 30, giving you <u>18=b</u>.

To check this, plug in your new known variable, as 270= 18* 30 /2. This will equal as 270=270, confirming 18in as the correct measurement.
3 0
3 years ago
Insert each of the following numbers between two consecutive multiples of 5: 13 37 48 61 93
DedPeter [7]
10 (13) 15
35 (37) 40
45 (48) 50
60 (61) 65
90 (93) 95
7 0
3 years ago
help please help please I need help please please please help out please I need helphelp please please I need help please please
poizon [28]

Answer:

9 & 1/4

Step-by-step explanation:

you have 3/4 and you subtract by 10, and since 3/4 is a decimal (0.75) you subtract it by 10 wich gives you 9 & 1/4

7 0
3 years ago
Read 2 more answers
PLS HELPP Help Solve for x <br>X =​
Basile [38]

Answer:

x = 9

Step-by-step explanation:

The big triangle is similar to smaller one so we can use the side lengths' proportion to find x:

7/4 = (x-3)+8/8

7/4 = (x+5)/8 cross multiply expressions

56 = 4x + 20 subtract 20 from both sides

36 = 4x divide both sides by 4

9 = x

4 0
2 years ago
Evaluate the following double integral where a = 2y
Keith_Richards [23]

Change the order of integration.

\displaystyle \int_0^1 \int_{2y}^2 \cos(x^2) \, dx \, dy = \int_0^2 \int_0^{x/2} \cos(x^2) \, dy \, dx \\\\ ~~~~~~~~ = \int_0^2 \cos(x^2) y \bigg|_{y=0}^{y=x/2} \, dx \\\\ ~~~~~~~~ = \frac12 \int_0^2 x \cos(x^2) \, dx

Substitute u=x^2 and du=2x\,dx.

\displaystyle \frac12 \int_0^2 x \cos(x^2) \, dx = \frac14 \int_0^4 \cos(u) \, du = \frac14 \sin(u) \bigg|_{u=0}^{u=4} = \boxed{\frac{\sin(4)}4}

4 0
1 year ago
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