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2 years ago

Celia bought a bag of 12 goldfish for $3.What is the cost of 1goldfish?

Mathematics

2 answers:

ahrayia [7]2 years ago

6 0

Answer:

0.25

Step-by-step explanation:

sweet [91]2 years ago

5 0

Answer:

0.25

Step-by-step explanation:

3÷12=0.25

12 goldfish for $3

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There are 2 pens for every 9 pencils. There is a total of 16 pens in the classroom. How many pencils are in the classroom? *

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3 years ago

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2 years ago

Joyce is trying to solve the equation y = x2 − 8x + 7 using the quadratic formula. She has made an error in one of the steps bel

kobusy [5.1K]

Answer:

x = 1 , 7

Step-by-step explanation:

Solution:-

- The given equation is as follows:

y = x^2 - 8x + 7

- We can solve the above equation by either making factors or by using Quadratic formula.

Factor Approach:

- Using the constant "7" at the end of the quadratic equation we will determine two integer multiples such that their additions/subtraction results in "-8".

- So the only factor of "7" are:

7 x 1 = 7

-7 x -1 = 7

- We see that addition/subtraction of first (7 , 1 ) does not results in "-8", However, the sum of ( -1 , -7 ) = -1 - 7 = -8. So the correct factors are ( -1 , -7 ). So we replace "-8x" with our factors "-1x" and "-7x":

x^2 -x -7x + 7 = 0

- Take common multiples out of pair of two terms:

x*(x-1) -7*(x-1) = 0

(x-7)*(x-1) = 0

- So we equate each term in bracket with "0" and evaluate the values of x:

(x-7) = 0 , x = 7

(x-1) = 0 , x = 1

- So the solution to the quadratic equation is:

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4 0

3 years ago

special deck of cards has 20 cards. Nine are green, seven are blue, and four are red. When a card is picked, the color of it is

Sever21 [200]

Answer:

Step-by-step explanation:

Given that special deck of cards has 20 cards. Nine are green, seven are blue, and four are red. When a card is picked, the color of it is recorded. An experiment consists of first picking a card and then tossing a coin

A) Sample space will have Green, Head, or Green, Tail .... Red, head, red, tail

No of elements in sample space = no of colours x no of outcomes in coin toss

= 4x2 = 8

B) A= getting (RT)

P(A) = Prob of getting red card and tail on coin

= P (R) *P(T)

= $\frac{4}{20} *\frac{1}{2} \\=\frac{1}{10}$

C) B be the event that a green or blue is picked, followed by landing a tail on the coin toss

B = getting green card and tail

Getting green card tail is mutally exclusive with red card and tail as there is no common element between green and blue.

D) C= red or green card is picked followed by tail.

Here A and C have a common element as getting red and tail. So not mutually exclusive

7 0

2 years ago