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vfiekz [6]
4 years ago
5

In an animal shelter, the ratio of dogs to cats is 5 to.There are 25 dogs. Write and solve a proportion to find the number c of

cats
Mathematics
1 answer:
pishuonlain [190]4 years ago
4 0

Answer:

5 cats

Step-by-step explanation:

  d/c = 5/1

    d = 25      Substitute in the proportion

25/c = 5/1     Multiply both sides by c

  25 = 5c/1

  25 = 5c      Divide each side by 5

    c = 5

There are five cats.

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125-13 = 112

112/2 = 56

The answer is C. 56
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London baked 4 batches of 48 cookies. She
valentina_108 [34]
16 cookies are in each bag, 4 x 48= 192 total cookies, divided by 12= 16
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-36x - 24 ≤ -6(5x + 12)​
puteri [66]

Answer:

x ≥ 8

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define inequality</u>

-36x - 24 ≤ -6(5x + 12)

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute -6:                         -36x - 24 ≤ -30x - 72
  2. Add 36 on both sides:         -24 ≤ 6x - 72
  3. Add 72 on both sides:          48 ≤ 6x
  4. Divide both sides by 6:         8 ≤ x
  5. Rewrite:                                  x ≥ 8

Here we see that any number <em>x</em> greater than or equal to 8 would work as a solution.

6 0
3 years ago
Simplify Negative two and one-third minus negative ten and one-sixth
aivan3 [116]
-2 1/3 - (- 10 1/6) = 
- 7/3 + 61/6 = 
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6 0
4 years ago
(CO 3) The weights of ice cream cartons are normally distributed with a mean weight of 20.1 ounces and a standard deviation of 0
Nata [24]

Answer:

The probability is 0.252 ⇒ 3rd answer

Step-by-step explanation:

* Lets revise how to find the z-score

- The rule the z-score is z = (M - μ)/σM , where

# M is the sample mean

# μ is the mean

# σM is the standard deviation of the sample mean (standard error)

-  The rule of σM = σ/√n , where n is the sample size

* Lets solve the problem

∵ The mean weight is 20.1 ounces

∴ μ = 20.1

∵ The standard deviation is 0.3 ounces

∴ σ = 0.3

∵ You randomly select 25 cartons

∴ n = 25

∵ Their mean weight is greater than 20.06

∴ M = 20.06

- Lets find σM

∵ σM = σ/√n

∴ σM = 0.3/√25 = 0.3/5 = 0.06

- Lets find z-score

∵  z-score = (M - μ)/σM

∴  z-score = (20.06 - 20.1)/0.06 = -0.04/0.06 = - 0.6670

- To find P(M > 20.06) you will asking to find the proportion of area

  under the standard  normal distribution curve for all z-scores > -0.670

- It can be read from a z-score table by referencing a z-score of -0.670

- Look to the attached table

∴ P(M > 20.06) = 0.2514

* The probability is 0.252

3 0
3 years ago
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