Here is a graph of <span>6x + 5y < 30</span>
You have the polygon MNOPQR which can be expressed as two rectangles pasted one next to each other.
To see the two rectangles in the picture, you can draw a line parallel to segment MR througn point N.
From the original picture you can state the dimensions of both rectangles.
Call S, the point where the line that you drew intercepts the segment RQ.
Then one rectangle is MNSR and the other rectangle is OPQS.
The measures of the sides of the rectangle MNSR are:
- the length of MN = length of SR = base
- the length of MR = the length of NS.= height
So its area is base * height, which you can all A1.
The measured of the rectangle OPQS are:
- segment OP = segment SQ = segment QR - segment SR = base
- segment PQ = segment OS = height
So its area is base * height, which you can call A2.
Then the area of the polygon MNOPQRS is A1 + A2. One of them is 9 u^2 and the other is what the answer is asking for, and that you have calculated above.
With this procedure you can tell the value needed.
No, it would leave a decimal
Answer:
The wrt=itten expressions are too difficult to interpret properly. I did my best but I don't see any of the answers as equivalent to <u>-3x - 2y, so please check my interpretations of the answer options.</u>
Step-by-step explanation:
"Negative 3 x minus one-half 4 y"
-3x- (1/2)4y
<u>or -3x - 2y</u>
<u>=====</u>
The answer options are too garbled for me to make sense of them. Are they:
1. 2 y minus 5 x minus one-half 2 y : 2y -5x - (1/2)2y; <u>y -5x</u> ?
2. 2 x Negative 2 x minus one-half 6 y : 2(-2x)- (1/2)6y; <u>-4x - 3y</u> ?
3. 3 x Negative 3 x minus three-fourths 4 y : 3x(-3x) - (3/4)4y; <u>-9x -3y</u> ?
4. one-fourth Negative 3 y minus three-fourths 7 y one-fourth minus 3 x:
(1/4)(-3y) - (3/4)7y - (1/4)(-3x); -(3/4)y -(21/4)y + (3/4)x; -(24/4)y + (3/4)x; ?
I don't see any of the answers as equivalent to <u>-3x - 2y, so please check my interpretations of the answer options.</u>
Hello,
7l=7×1000=7000 ml
Bye :-)
