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Ugo [173]
3 years ago
8

Calculate the above formula, expressing the answer in scientific notation with the correct number of significant figures

Mathematics
1 answer:
mariarad [96]3 years ago
4 0
\frac{8.86 + 1.0 \times 10^{-3}} {3.610 \times 10^{-3}}=\frac{8.86 + 0.001} {0.00361} \\  \\ =\frac{8.861} {0.00361}=2,454.57=\bold{2.455\times10^3}
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Solve for y.<br> 15y - -9y + -10y = 14<br> y =<br> Submit
Tems11 [23]

Answer:

I think y=1

Step-by-step explanation:

15y+9y= 24y

24y-10y=14y

divide 14y by 14 and get just y and divide 14 by 14 to get one

y=1

8 0
3 years ago
Find the distance between (6, 0) and (10, 3).
yulyashka [42]
A 5 units I believe
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2 years ago
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3. If 2p + q = 11 and p + 2q = 13, then<br> p+q=<br> (A) 6<br> (B) 8<br> (C) 9<br> (D) 12<br> (E) 18
frozen [14]
Answer:
(C) 9

Step by step:
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3 years ago
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Giving brainliest! Please show the working out
tiny-mole [99]

Answer:

see explanation

Step-by-step explanation:

(a)

OC = OB ( both radii of the circle )

Thus Δ BOC is isosceles with congruent base angles.

∠ BOC = ∠ BCO = 50°

(b)

∠ ACB = 90° ( angle in a semicircle ), then

∠ ACO = 90° - 50° = 40°

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Thus Δ ACO is isosceles with congruent base angles.

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7 0
3 years ago
Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar
Brrunno [24]

The distance between the two points is d=8.6m

The polar coordinate of A is \left(4.47,296.57\right)

The polar coordinate of B is \left(4.24,135\right)

Explanation:

The two points are A(2,-4) and B(-3,3)

The distance between two points is given by,

d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6

Thus, the distance between the two points is d=8.6m

The polar coordinates of A can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting A(2,-4), we get,

Distance = \sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47

tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43

To make the angle positive, let us add 360,

\theta=360-63.43=296.57

The polar coordinate of A is \left(4.47,296.57\right)

Similarly, The polar coordinate of B can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting B(-3,3), we get,

Distance = \sqrt{(3)^{2}+(3)^{2}}=4.24

tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45

To make the angle positive, let us add 360,

\theta=180-45=135^{\circ}

The polar coordinate of B is \left(4.24,135\right)

5 0
3 years ago
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