<span> 80/-40=-40/20=-2,
the sequence: 80, -40, 20 is a geometric sequence
its general formula is Vn+1 = q Vn, where q= -2,
if we put </span>Vn+1 = f(x)
<span> Vn = x
so we have f(x)= -2x so the graph that represents the sequence is graph of linear equation
</span>
Answer:
hviygkcgc fgx
Step-by-step explanation:
The equation of line perpendicular to given line through (-6,7) is:
![y=\frac{1}{6}x+8](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B6%7Dx%2B8)
Further explanation:
Given equation of line is:
![6x+y=3\\y= -6x+3](https://tex.z-dn.net/?f=6x%2By%3D3%5C%5Cy%3D%20-6x%2B3)
The co-efficient of x is the slope of given line.
Let m1 be the slope of given line
and
m2 be the slope of line perpendicular to given line
Then
![m_1=-6](https://tex.z-dn.net/?f=m_1%3D-6)
Product of slopes of perpendicular lines is -1
![m_1*m_2 = -1\\-6*m_2=-1\\m_2=\frac{-1}{-6}\\m_2=\frac{1}6}](https://tex.z-dn.net/?f=m_1%2Am_2%20%3D%20-1%5C%5C-6%2Am_2%3D-1%5C%5Cm_2%3D%5Cfrac%7B-1%7D%7B-6%7D%5C%5Cm_2%3D%5Cfrac%7B1%7D6%7D)
The equation of new line can be written as:
![y=m_2x+b\\](https://tex.z-dn.net/?f=y%3Dm_2x%2Bb%5C%5C)
Putting m2
![y=\frac{1}{6}x+b](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B6%7Dx%2Bb)
To find the value of b, we will put (-6,7) in equation
![7=\frac{1}{6}(-6)+b\\7=-1+b\\b=7+1\\b=8](https://tex.z-dn.net/?f=7%3D%5Cfrac%7B1%7D%7B6%7D%28-6%29%2Bb%5C%5C7%3D-1%2Bb%5C%5Cb%3D7%2B1%5C%5Cb%3D8)
Putting the values of b and m in general equation
![y=\frac{1}{6}x+8](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B6%7Dx%2B8)
Keywords: Slope, Point-slope form, perpendicular lines
Learn more about perpendicular lines at:
#LearnwithBrainly
Answer: 12
Step-by-step explanation:
if there are 2 people then doing the same job then that means divide by two so 8 which is off the 28 , 8 divided by 2 is 4, then, that makes 24 , and 24 divided by 2 is 12 so the answer is 12
Answer:
Step-by-step explanation:
slopes and equations:
find the equation thur ( 6,1 ) and (-2,-3)
find the slope m
m = (y2-y1) / (x2-x1 )
m = (-3 - 1) / (-2 -6)
m = -4 / -8
m = 1/2
now use the point-slope formula with our known slope
y-y1 = m(x-x1)
y-1 = 1/2(x-6)
y - 1 = 1/2x -3
y = 1/2x -3 +1
y =
x -2
Find the equation parallel to y = 3x + 6 and thur (0,1)
Parallel means the same slope, the slope is 3 for the equation above.
use the slope-intercept formula again with the point given and the slope 3
y-1 = 3(x -0)
y - 1 = 3x
y = 3x +1
Find the equations perpendicular to 2x + y = 8 and the same y intercept as 4y = x + 3.
put both equations into proper form
y = -2x +6
y =
x + ![\frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D)
perpendicular means reciprocal slope and change the sign, the 2nd equation has an intercept of
, so
y = 1/2x + ![\frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D)
there you go Amanda :)