X + y = 61
y - 3x = 5...y = 3x + 5
x + (3x + 5) = 61
4x + 5 = 61
4x = 61 - 5
4x = 56
x = 56/4
x = 14
y - 3x = 5
y - 3(14) = 5
y - 42 = 5
y = 42 + 5
y = 47
ur 2 numbers are 14 and 47
Answer:
At the store every lollipop coasts $2 you have a coupon that will give you $2 off any purchase.
Step-by-step explanation:
2= the coast for each single lollipop
x= the number of lollipops you buy
-2= the $2 taken off your purchase due to your coupon
Answer:
Option b) Increase the sample mean
Step-by-step explanation:
Given that a researcher selects a sample from a population with μ = 30 and uses the sample to evaluate the effect of a treatment. After treatment, the sample has a mean of M = 32 and a variance of s2 = 6.
This is a paired test with test statistic
=mean diff/std error
Mean difference would increase if sample mean increases.
This would increase the test statistic
Or otherwise decrease in variance will increase the test statistic
Or Increase in sample size would also increase test statistic
Of all these the II option is definite in increasing the likelihood of rejecting the null hypothesis because this would definitely increase the chances of rejecting H0.
Others may also have effect but not as much direct as sample mean difference.
Because variance and sample size have influence only upto square root of the difference.
