Answer:
95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C
Step-by-step explanation:
The confidence interval for a proportion is given as [p +/- margin of error (E)]
p is sample proportion = 870/1,100 = 0.791
n is sample size = 1,100
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (z) at 5% significance level is 1.96.
E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024
Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767
Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815
95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.
You are only showing one pair of triangles
Answer:
d
Step-by-step explanation:
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Expansions and compressions are transformations that change the length or width of the graph of a function.
To graph y = a*f (x)
if a> 1, the graph of y = f (x) is expanded vertically by a factor a.
We have then:
f (x) = 2/5 x ^ 2-2
The function g (x) is a vertical stretch of f (x) by a factor of 2:
g (x) = 2f (x)
g (x) = 2 (2/5 x ^ 2-2)
g (x) = 4/5 x ^ 2-4
Answer:
The equation of g (x) is:
g (x) = 4/5 x ^ 2-4
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Answer:
- f(x²) = x² +5
- (f(x))² = x² +10x +25
Step-by-step explanation:
Put the argument in place of x and evaluate the desired expression.
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1. f(x²) = x² + 5 . . . . . . straight substitution for x
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2. (f(x))² = (x +5)²
= (x +5)(x +5) = x(x +5) +5(x +5) = x² +5x +5x +25
(f(x))² = x² +10x +25
