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Mumz [18]
3 years ago
6

Evaluate the expression, given functions f and h: f(x) = 3x − 1, h(x) = −2x2 + 3x − 7.

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

Answer:

Your answer is 27

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Mr. Torres took his students to the dolphin show. Each row in the stadium had 9 seats. One adult sat at each end of a row, and e
iragen [17]

Answer:

There were 4 adults; including Mr. Torres

Step-by-step explanation:

- Each row in the stadium had 9 seats

- Mr. Torres sat by himself; he sat on a row with nobody else (no students, no adults)

- The arrangement of the students and the adults who sat with them on same row is:   A  S  S  S  A  S  S  S  A

              1   2  3  4  5  6  7  8  9

since 1 adult sat at each end of a/the row and each group of 3 students was seated between 2 adults.

So the total number of adults that were present = 3 + 1 = 4

5 0
2 years ago
Y= 2x-8,what is the slope and the y-intercept
Natalija [7]
Hi is the answer so this makes it okay to do thing when you have it
8 0
3 years ago
HELP PLEASEEE!!!
kodGreya [7K]

Answer: The correct answers are $45.15, $247.25 and $129

Step-by-step explanation:

In order to solve the problems you need to multiply each percentage by his gross monthly pay.

$2,150 x .021 = $45.15

$2,150 x .115 = $247.25

$2,150 x .06 = $129

4 0
3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
2 years ago
29. ERROR ANALYSIS Describe and correct the error in
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Answer:

eeeeeeeeeeeeeeeeeeeeeeeeeee nose perdon xd

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