Answer: The bacteria transformed with this particular plasmid will form white colonies on the plates containing ampicillin and Xgal.
Explanation: The lacZ gene produces an enzyme called β-galactosidase which is responsible for the breakdown of lactose into glucose and galactose. The lacZ gene is one of the three genes (the other two being lacA and lacY) of the lac operon which is responsible for the transport and mechanism of lactose in E. coli and many other bacteria.
In recombinant DNA technology, when a plasmid is to be used to transform a host cell, such markers are used to help screen the transformed cells from the ones that have not taken up the plasmid. Xgal present in the plates is an artificial substrate which is hydrolyzed by
β-galactosidase into 5-bromo-4-chloro-indoxyl which will dimerize and oxidise into 5,5'-dibromo-4,4'dichloro-indigo. This is a blue pigment which will give blue color to the bacterial cells. Introducing a DNA fragment in this lacZ gene will make it non-functional so it will not be able to produce the enzyme.
Therefore, when a bacterial cell is transformed with a plasmid containing ampicillin resistance gene and a DNA fragment introduced in the lacZ gene and then grown on plates containing ampicillin and Xgal, white colored colonies will appear. The white colonies will show the bacterial cells that have successfully taken up the plasmid with the DNA fragment incorporated in the lacZ gene as this will render the gene non-functional and will not produce β-galactosidase which will breakdown Xgal to give blue colonies. Since the plates contain ampicillin, only the bacterial cells that have been successfully transformed with the plasmid ( the ones that have the DNA fragment and the ones without it) will grow as the ampicillin resistance will give them resistance against ampicillin in the plates. The bacterial cells that have not taken up the plasmid will not be resistant to ampicillin and will not form colonies on the plate.
This is called blue-white screening which is used to identify successfully transformed host cells. A picture of this is given in the attachment, taken from the following website:
https://www.mun.ca/biology/scarr/Blue_&_White_Colonies.html
Answer:
When organisms use urea, ammonia is generated during incubation, which makes the reaction of these media alkaline
Explanation:
Urea broth preparation:
Suspend 3.87 grams of the medium in 100 ml of distilled water without heating. When the powder dissolves, sterilize by filtration. Dispense quantities of 0.5 to 2 ml in small sterile tubes. Larger volumes may be used but the reactions will be slower. Do not sterilize in autoclave.
Do not boil the medium.
If no filter is available, the medium can be sterilized at 100-110 ° C for 10 minutes. If the medium is prepared and inoculated immediately, it provides good results without sterilization.
Answer: False
Explanation:
The urethra is a tube which runs from the bladder to the end of the penis. It functions by carrying the urine and semen outside the male body.
Urethra is made of two components. Prostatic urethera is the part that runs from the bladder through the prostrate.
The penis is only organ which carries both the fluids out of the body.