Ask question

Ask question

All categories

3 years ago

10

What do these terms have in common? google, yahoo!, bing they are important books. they are internet search engines. they are wo

rd processing programs.

Computers and Technology

1 answer:

Vlada [557]3 years ago

7 0

They are Internet search engines.

You might be interested in

__ means having a current knowledge and understanding of computers, mobile devices, the web, and related technologies.

Brrunno [24]

Answer:

Digital literacy

Explanation:

Digital Literacy means having a current knowledge and understanding of computers, mobile devices, the web, and related technologies.

Brainliest plz

8 0

4 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago

Write a program that reads a floating-point number from the user and prints "zero", "positive" or "negative"

Lorico [155]

```
#!/usr/local/bin/python3

foo = float( input( "Enter a number: " ) )
if( foo < 0.0 ):
    print( "negative" )
elif( foo > 0.0 ):
    print( "positive" )
else
    print( "zero" )

exit( 0 )
```

3 0

3 years ago

ICE Princess25 [194]

1. True
2. Usually true, but it depends on the search engine you're using. For example, Google lets you search for several words without commas.

3 0

3 years ago

Your company shares a building with a competitor's branch office. Recently, you noticed that some computers other than company c

professor190 [17]

<u>The wireless network:</u>

Wireless networking and internet access are essentials when it comes to the smooth functioning of an enterprise. Certain information can be transferred from one computer to another within a specified if they are connected to a network.

In this case, as the company shares the building with the branch office of a rival company there may be repercussions. First of all, the company's wireless network should be equipped with a strong password and it should be changed regularly too.

Next, the officials responsible for networking should also monitor the range of their wireless network. There is no point in keeping the range of wireless network wide as it is to be used by employees only and they can access it on the company's premises.

5 0

3 years ago