sin(3)+cos(3)sin(3)tan(3)3=0=−cos(3)=−1=−4+,∈ℤ=−12+3
sin(3x)+cos(3x) =0 sin(3x) =−cos(3x) tan(3x) =−1 3x =−
π
4
+kπ,k∈
Z
x =−
π
12
+
k
π
3
Since −<<
−
π
<
x
<
π
, −2≤≤3
−
2
≤
k
≤
3
. Thus, the solution set is
{−34,−512,−12,4,712,1112}
Answer:b
Step-by-step explanation:
Answer:
4-
-
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
The vertex form of f(x) is
f(x) = (x - h)² + k
where (h, k) are the coordinates of the vertex
To obtain this form use the method of completing the square
add/subtract ( half the coefficient of the x- term )² to x² + 14x
f(x) = x² + 2(7)x + 49 - 49 + 36
= (x + 7)² - 13
The minimum value of f(x) is the y- coordinate of the vertex
vertex = (- 7, - 13), that is minimum value = - 13
Answer:
3.7×1.2=3+0.7+0.6+0.14=4.44
Step-by-step explanation:
I added all the choices together I picked the one that had the same answer. Good luck!
