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Sergeu [11.5K]
3 years ago
13

Solve each inequality 4x-3>1

Mathematics
1 answer:
Phantasy [73]3 years ago
5 0
So you have 4x-3>1. add three to both sides to get 4x>4. divide both sides by 4 to get x >1, so x has to be greater than one.
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The number is 8

Step-by-step explanation:

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2x=16

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To check

8×2=16

16+5=21

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(½) (6x + 3) = 7 – (3x + 1)
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\tt Step-by-step~explanation:

To solve for x, we have to remember to isolate the variable.

\tt Step~1:

For 1/2, we can make that 0.5, since their values are equivalent. Our equation:

\tt (0.5)(6x+3)=7-(3x+1)

Let's distribute the 0.5 first.

\tt 0.5*6x=3x\\0.5*3=1.5

\tt Step~2:

Now, let's simplify the right side of the equation. We have to distribute the negative to 3x and 1.

\tt -1*3x=-3x\\-1*1=-1

Then, we simplify the entire expression.

\tt 7-3x-1=-3x+6

\tt Step~3:

Our equation now:

\tt 3x+1.5=-3x+6

Let's add 3x to the right and 3x to the left to simplify the -3x on the right side of the equation.

\tt 3x(+3x)+1.5=-3x (3x)+6\\6x+1.5=6

\tt Step~4:

Let's do the same thing we did in Step 3 to 1.5. Subtract 1.5 on both sides of the equation.

\tt 6x+1.5(-1.5)=6(-1.5)\\6x=4.5

\tt Step~5:

Finally, we divide both sides by 6 to isolate x.

\tt \frac{6x}{6} =x\\\frac{4.5}{6}= 0.75~or~\frac{3}{4}

\large\boxed{\tt Our~final~answer:~x=0.75~(or~\frac{3}{4})}

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